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MrRa [10]
3 years ago
5

WILL DO ABSOLUTELY ANYTHING FOR THIS ONE HELP ASAP TIMES

Mathematics
1 answer:
Rina8888 [55]3 years ago
3 0

Given:

The graph of a function y=h(x).

To find:

The interval where h(x)>0.

Solution:

From the given graph graph it is clear that, the function before x=0 and after x=3.6 lies above the x-axis. So, h(x)>0 for x and x>3.6.

The function between x=0 and x=3.6 lies below the x-axis. So, h(x) for 0.

Now,

For -1, the graph of h(x) is above the x-axis. So, h(x)>0.

For 0, the graph of h(x) is below the x-axis. So, h(x).

For 1, the graph of h(x) is below the x-axis. So, h(x).

Only for the interval -1, we get h(x)>0.

Therefore, the correct option is A.

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A store sells televisions for $360 and DVD burners for $270. The entire stock is worth $52,920 and there are a total of 164 tele
bogdanovich [222]

Answer:  96 Televisions, 68 DVD burners

<u>Step-by-step explanation:</u>

Let T represent the quantity of televisions

Let D represent the quantity of DVD burners

<u>Given:</u>

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value of DVD burners (D) = 270

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<u>Equations:</u>

Value: 360T + 270D = 52,920

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We can solve the system of equations using the Elimination Method:

-1(360T + 270D = 52,920) →  -360T - 270D = -52,920

  360(T + D = 164) →                <u>360T + 360D</u> = <u>59,040 </u>

                                                                90D = 6,120

                                                              <u> ÷90   </u>  <u> ÷90    </u>

                                                                     D = 68

Input the value of D into one of the equations to solve for T

T + D = 164

T + 68 = 164

      T   = 96

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