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3 years ago

(√2+√3) ^2answer faaaaaaaaaaaaast

Mathematics

2 answers:

ad-work [718]3 years ago

7 0

Answer:

2.5

Step-by-step explanation:

Igoryamba3 years ago

3 0

Answer:

$thank \: you$

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Please help me thank you

Katen [24]

Answer: y=-0.5x+4.5

Step-by-step explanation: y=mx+b, m is the slope = -1/2 or -0.5, and b is the y-int, which is 4.5

3 0

3 years ago

I NEED HELP PLEASE !!!!!

erastovalidia [21]

Answer:

c= (f-d)/ab

Step-by-step explanation:

abc+d = f
Subtract f from both sides so abc= f-d
Divide by ab from both sides so c = (f-d)/ab

8 0

3 years ago

4(n+2+2n+5+n+6)=-32 How do you show the problem?

yarga [219]

Answer:

n = -21/4 <em>or </em>-5.25

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Factoring Quadratic Expressions:<br> 5p^2 - p - 18

Dennis_Churaev [7]

$5 p^{2} -p-18$

$5 p^{2}-10p+9p-18$

$5p(p-2)+9(p-2)$

$(p-2)(5p+9)$

3 0

3 years ago

A box with a hinged lid is to be made out of a rectangular piece of cardboard that measures 3 centimeters by 5 centimeters. Six

kherson [118]

Answer:

x = 0.53 cm

Maximum volume = 1.75 cm³

Step-by-step explanation:

Refer to the attached diagram:

The volume of the box is given by

$V = Length \times Width \times Height \\\\$

Let x denote the length of the sides of the square as shown in the diagram.

The width of the shaded region is given by

$Width = 3 - 2x \\\\$

The length of the shaded region is given by

$Length = \frac{1}{2} (5 - 3x) \\\\$

So, the volume of the box becomes,

$V = \frac{1}{2} (5 - 3x) \times (3 - 2x) \times x \\\\V = \frac{1}{2} (5 - 3x) \times (3x - 2x^2) \\\\V = \frac{1}{2} (15x -10x^2 -9 x^2 + 6 x^3) \\\\V = \frac{1}{2} (6x^3 -19x^2 + 15x) \\\\$

In order to maximize the volume enclosed by the box, take the derivative of volume and set it to zero.

$\frac{dV}{dx} = 0 \\\\\frac{dV}{dx} = \frac{d}{dx} ( \frac{1}{2} (6x^3 -19x^2 + 15x)) \\\\\frac{dV}{dx} = \frac{1}{2} (18x^2 -38x + 15) \\\\\frac{dV}{dx} = \frac{1}{2} (18x^2 -38x + 15) \\\\0 = \frac{1}{2} (18x^2 -38x + 15) \\\\18x^2 -38x + 15 = 0 \\\\$

We are left with a quadratic equation.

We may solve the quadratic equation using quadratic formula.

The quadratic formula is given by

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Where

$a = 18 \\\\b = -38 \\\\c = 15 \\\\$

$x=\frac{-(-38)\pm\sqrt{(-38)^2-4(18)(15)}}{2(18)} \\\\x=\frac{38\pm\sqrt{(1444- 1080}}{36} \\\\x=\frac{38\pm\sqrt{(364}}{36} \\\\x=\frac{38\pm 19.078}{36} \\\\x=\frac{38 + 19.078}{36} \: or \: x=\frac{38 - 19.078}{36}\\\\x= 1.59 \: or \: x = 0.53 \\\\$