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2 years ago

(√2+√3) ^2answer faaaaaaaaaaaaast

Mathematics

2 answers:

ad-work [718]2 years ago

7 0

Answer:

2.5

Step-by-step explanation:

Igoryamba2 years ago

3 0

Answer:

$thank \: you$

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Which set of side lengths is a pythagorean triple

Neko [114]

Several examples of side lengths that are Pythagorean triples are the following with the corresponding side lengths A, B, C:

(5, 12, 13), (7, 24, 25), (3, 4, 5)

-E :)

4 0

3 years ago

I NEED THIS ASAP- Point A is located at (-5, -8). Point A is reflected across the X-axis to create point B. What is point B?

Rasek [7]

Answer:

(5,-8)

Step-by-step explanation:

if it is reflected across the X axis and this is in quadrant 3 that means if it was reflected it would fall in quadrant 2

6 0

3 years ago

There are 24 students in a science class .Mr Sato will give each pair of students 3 magnets .so far,Mr Sato has given 9 pair of

BartSMP [9]

9 pairs = 18 people
24 - 18 = 6
6 divided by 2 = 3 pairs
3 magnets for 3 pairs is 9 magnets.

5 0

3 years ago

The distance between the points (-1, -6) and (-19, -6) is units

Vladimir [108]

Answer:

Step-by-step explanation:

$\sqrt{ {( - 9 - - 1)}^{2} + {( - 6 - - 6)}^{2} }$

$\sqrt{ {( - 18)}^{2} }$

$\sqrt{324}$

3 0

2 years ago

If you have a cube measuring 1 unit on each side, how many of those cubes would fit into a space 2 units by 3 units by 4 units

alisha [4.7K]

Given:

Measure of a cube = 1 unit on each side.

Dimensions of a space 2 units by 3 units by 4 units.

To find:

Number of cubes that can be fit into the given space.

Solution:

The volume of cube is:

$V_1=a^3$

Where, a is the side length of cube.

$V_1=(1)^3$

$V_1=1$

So, the volume of the cube is 1 cubic units.

The volume of the cuboid is:

$V_2=l\times b\times h$

Where, l is length, w is width and h is height.

Putting $l=2,b=3,h=4$ , we get

$V_2=2\times 3\times 4$

$V_2=24$

So, the volume of the space is 24 cubic units.

We need to divide the volume of the space by the volume of the cube to find the number of cubes that can be fit into the given space.

$n=\dfrac{V_2}{V_1}$

$n=\dfrac{24}{1}$

$n=24$

Therefore, 24 cubes can be fit into the given space.

3 0

3 years ago

(√2+√3) ^2answer faaaaaaaaaaaaast​

(√2+√3) ^2answer faaaaaaaaaaaaast