In this problem, we are asked to determine the degree of the given expression 12X4 - 8X + 4X2 -3. To answer this, first, we need to arrange the mathematical expression in descending order with respect to its power such as the new arrangement will become 12x4 + 4x2 -8x -3. The degree is clearly visible and it is 4. Therefore, the answer to this problem is the letter "B" which is 4.
The average rate of change of credit card is $ 401.79 /year.
<h3>
What is Average Rate?</h3>
- A single rate that is a weighted average of the different rates that are applicable to property in various locations.
- An average is a single number calculated as the average of a set of numbers, typically calculated as the sum of the numbers divided by the total number of numbers in the set (the arithmetic mean).
<u>Solution</u>
The difference of credit card debt between the year 2006 and 1992 = 8900 - 3275 = $5625
The difference of years between the year 2006 and 1992 = 2006 - 1992 = 14
average rate of change of credit card debt with respect to time = 
average rate = 
= $ 401.79 / year
know more about average numerical brainly.com/question/18296887
#SPJ4
The intervals are given as follows:
- In range notation: [-282, 20,320].
- In set-builder notation: {x|x ∈ ℝ, -282 <= x <= 20,320}
<h3>What is the range of elements notation for interval?</h3>
The range of elements notation for interval is given by:
[a,b].
In which:
In this problem these values are given by:
a = -282, b = 20,320.
Hence the interval in range notation is given by:
[-282, 20,320].
<h3>How to write the interval in set-builder notation?</h3>
The same interval can be written as follows, using set-builder notation?
{x|x ∈ ℝ, a <= x <= b}
Hence, for the situation described in this problem, the set-builder notation for the values is:
{x|x ∈ ℝ, -282 <= x <= 20,320}
More can be learned about notation of intervals at brainly.com/question/27896097
#SPJ1
Answer:
Step-by-step explanation:
<u>This is an AP with:</u>
- The first term a₁ = 12
- Common difference d = 3
- Number of terms n = 40
<u>Number of the seats:</u>
- Sₙ = 1/2*n(a₁ + aₙ) = 1/2n(2a₁ + (n - 1)d)
- S₄₀ = 1/2*40(12*2 + 39*3) = 2820 seats
<u>Formula of nth term:</u>
- aₙ = a₁ + (n - 1)d
- aₙ = 12 + (n - 1)*3 = 12 + 3n - 3 = 3n + 9
- aₙ = 3n + 9
Repeating.................................
