Begin by adding 4.9x to both sides.
1.3> 11.1 + 4.9x This way you never have to remember to turn the > into < when dividing by a minus.
Subtract 11.1 from both sides
-9.8 < 4.9x Divide by 4.9
-9.8 / 4.9 < x
-2 < x
Question:
The cost of 12 kg sugar is $240 what will be the cost of 3 kg sugar.
Given:
- Cost of 12 kg sugar = $240
To find?
Answer :
<u>To find </u><u>c</u><u>o</u><u>s</u><u>t</u><u> </u><u>of</u><u> </u><u>3kg sugar first we have to find cost of 1 kg sugar</u><u>.</u>
- Cost of 1 kg sugar = Cost of total no. of sugar ÷Total sugar
- Cost of 1 kg sugar = $240/12
- Cost of 1 kg sugar = $20
<u>Now Let's find cost of 3 kg sugar</u>
Cost of 3kg sugar = total no of sugar ×Cost of 1 kg sugar
Cost of 3kg sugar = 3×$20
Cost of 3kg sugar = $60
95% percent that friend is not going to pay you back
Answer:
75
Step-by-step explanation:
We line up the tens place of 33 and 42 as well as the ones place so that it looks like:
33
+42
--------
Then we add first the ones, which is 3 + 2 for 5. Then we add the tens together, 3 + 4 is 7. We put the five first since its in the ones place and the 7 second since its in the tens place for 75.
