Unfortunately there isn't enough information.
Check out the diagram below. We have segment BC equal to 120 meters long. Points B, C, D and E are all on the edge of the same circle. According to the inscribed angle theorem, angles BDC and BEC are congruent. This shows that the surveyor could be at points D or E, or the surveyor could be anywhere on the circle. There are infinitely many locations for the surveyor to be at, which leads to infinitely many possible widths of this canal.
Answer D.
Insert (2, 2) in for x and y in the equations.
2(2)+ 3(2) = ?
? = 10
4(2) + 5(2) = ?
? = 18
-45+18x is the answer
Hope this helped <3
It should be a 10% tip. To simplify the answer, The decimal moves one space (which would be equal to a tenth) so it’s a 10%
The corresponding homogeneous ODE has characteristic equation 
with roots at 
, thus admitting the characteristic solution
For the particular solution, assume one of the form
Substituting into the ODE gives
Then the general solution to this ODE is
Assume a solution of the form
Substituting into the ODE gives
so the solution is
Assume a solution of the form
Substituting into the ODE gives
so the solution is
