Question

(x 2 + 3) (x 3 + 4x)(x 2 + x - i - xi) = 0

Answer 1

The possible values of x according to the give. equation are; 0, ±√3i, ±2i, i, -1.

What are the possible values of x?

The possible values of x in the equation given in the task content represent the zeroes of the equation and can be determined as follows;

(x²+3) (x³+4x) (x²+x-i-xi) = 0.

Hence, by further factorisation; we have;

x(x²+3) (x²+4) (x-i) (x+1) = 0.

The possible values of x are therefore;

x = 0;

x²+3 = 0; x = ±√3i

x² +4 = 0; x = ±2i

x -i = 0; x = i.

x +1 = 0; x = -1

Read more on zeros of an equation;

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