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sdas [7]
2 years ago
7

(x 2 + 3) (x 3 + 4x)(x 2 + x - i - xi) = 0

Mathematics
1 answer:
iogann1982 [59]2 years ago
6 0

The possible values of x according to the give. equation are; 0, ±√3i, ±2i, i, -1.

<h3>What are the possible values of x?</h3>

The possible values of x in the equation given in the task content represent the zeroes of the equation and can be determined as follows;

(x²+3) (x³+4x) (x²+x-i-xi) = 0.

Hence, by further factorisation; we have;

x(x²+3) (x²+4) (x-i) (x+1) = 0.

The possible values of x are therefore;

x = 0;

x²+3 = 0; x = ±√3i

x² +4 = 0; x = ±2i

x -i = 0; x = i.

x +1 = 0; x = -1

Read more on zeros of an equation;

brainly.com/question/20896994

#SPJ1

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<h2>Answer:</h2>

<em><u>The truck cannot pass safely under the bridge. The truck is 13 inches taller than the maximum height.</u></em>

<h2>Step-by-step explanation:</h2>

In the question,

The maximum height of the vehicle which is capable of passing under the bridge is 12 feet and 5 inches.

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162 - 149 = 13 inches

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I clearly don't know how to do it if i did i wouldn't be asking for help.
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Step-by-step explanation:

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