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Veronika [31]
3 years ago
12

You went to Disney World by car. The trip there took 6 hours. On the way home, people were evacuating for a possible hurricane s

o your speed decreased by 20 m/hr and it took 10 hours to get home. How fast was the car going on the way there? How fast was it going on the way back home?
Mathematics
1 answer:
slavikrds [6]3 years ago
3 0

Answer:

a) on the way there, the speed = 50 m/hr

b) on the way back home, speed = 30 m/hr

Step-by-step explanation:

speed (s) = \frac{distance(d)}{time(t)} \\distance = speed\ \times\ time

on the way to Disney land:

distance = d

speed = s

time = t = 6 hours

d = s × t

d = s × 6

d = 6s - - - - - (1)

On the way back:

speed decreased by 20m/hr

This means that s₂ = (s - 20)m/hr

time = t₂ = 10 hours

∴ d = s₂ × t₂

d = (s - 20) × 10

d = 10s - 200  - - - - (2)

<em>Note that the distance is the same to and from disney land, therefore, equation (1) equals equation (2)</em>

∴ 6s = 10s - 200

<em>collecting like terms:</em>

10s - 6s = 200

4s = 200

∴ s = 200 ÷ 4

s = 50 m/hr

Therefore on the way there, the car was moving at a apeed of 50m/hr

speed on the way back home (s₂) = (s - 20) m/hr

∴ s₂ = 50 - 20

s₂ = 30 m/hr

Therefore on the way back home the speed was 30 m/hr

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A survey showed that 35% of the students prefer plain white milk over chocolate milk. If the school has 1200 students. How many
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780 students prefer chocolate milk.

Step-by-step explanation:

Let,

the total percentage = 100%

Students who prefer plain white milk = 35%

Students who prefer chocolate milk = 100 - 35 = 65%

Number of students = 1200

No. of students who prefer chocolate milk = 65% of total students

No. of students who prefer chocolate milk = \frac{65}{100}*1200

No. of students who prefer chocolate milk = \frac{78000}{100}\\

No. of students who prefer chocolate milk = 780

780 students prefer chocolate milk.

Keywords: percentage, subtraction

Learn more about subtraction at:

  • brainly.com/question/11253316
  • brainly.com/question/11258952

#LearnwithBrainly

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The ages of the members of the Chess Club and the Debate Team at Jana’s school are shown in the box plots. Which statement is tr
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Answer:

C lul

Step-by-step explanation:

brainly.com/question/22583943

(The majority of the members in each club are between 15 and 17 years old.)

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2 years ago
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Round 67,436,828,104 to the nearest million
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theresa baked cookies to share with her friends. she split the cookies into 8 equal groups. if each friend got 6 cookies, how ma
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The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e
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Answer:

The 95% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.2087, 0.2507).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

Suppose a sample of 1537 tenth graders is drawn. Of the students sampled, 1184 read above the eighth grade level. So 1537 - 1184 = 353 read at or below this level. Then

n = 1537, \pi = \frac{353}{1537} = 0.2297

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

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The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2297 + 1.96\sqrt{\frac{0.2297*0.7703}{1537}} = 0.2507

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