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3 years ago

5

A ride at a carnival has two types of cars for children to ride. One type has 2 seats and one has 4 seats. There are 25 cars, an

d they can seat a total of 70 children, how many 4-seated cars are there?

1 answer:

CaHeK987 [17]3 years ago

5 0

Answer:

There are 10 and 4 seated cars

Step-by-step explanation:

I hope this helps you

You might be interested in

The nutrition label for Oriental Spice Sauce states that one package of sauce has 1100 milligrams of sodium. To determine if the

lora16 [44]

Answer:

We conclude that the sodium content is same as what the nutrition label states.

Step-by-step explanation:

We are given that the nutrition label for Oriental Spice Sauce states that one package of sauce has 1100 milligrams of sodium.

The FDA randomly selects 40 packages of Oriental Spice Sauce and determines the sodium content. The sample has an average of 1088.64 milligrams of sodium per package with a sample standard deviation of 234.12 milligrams.

<u><em /></u>

<u><em>Let </em></u> $\mu$ <u><em> = average sodium content.</em></u>

So, Null Hypothesis, $H_0$ : $\mu$ = 1100 milligrams {means that the sodium content is same as what the nutrition label states}

Alternate Hypothesis, $H_A$ : $\mu$ $\neq$ 1100 milligrams {means that the sodium content is different from what the nutrition label states}

The test statistics that would be used here <u>One-sample t test statistics</u> as we don't know about population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n}}}$ ~ $t_n_-_1$

where, $\bar X$ = sample average sodium content = 1088.64 milligrams

s = sample standard deviation = 234.12 milligrams

n = sample of packages of Oriental Spice Sauce = 40

So, <u><em>test statistics</em></u> = $\frac{1088.64-1100}{\frac{234.12}{\sqrt{40}}}$ ~ $t_3_9$

= -0.307

The value of z test statistics is -0.307.

<em>Since, in the question we are not given the level of significance so we assume it to be 5%. </em><em>Now, at 0.05 significance level the t table gives critical values of -2.0225 and 2.0225 at 39 degree of freedom for two-tailed test.</em><em> </em>

<em>Since our test statistics lies within the range of critical values of t, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which </em><em><u>we fail to reject our null hypothesis</u></em><em>.</em>

Therefore, we conclude that the sodium content is same as what the nutrition label states.

3 0

3 years ago

Do you know how set is going { London,Paris,<br> Stockholm,.....} ?

drek231 [11]

Answer: They're capitals of cities.

Step-by-step explanation:

You could continue the set with Madrid, Bucharest, Sofia, Luxembourg, Berlin, Rome, Athens... and so on.

4 0

3 years ago

Find the equation of a line, in slope-intercept fotm of a line that passes through the point (9,2) and is perpendicular to the l

cricket20 [7]

Considering the definition of perpendicular line, the equation of of perpendicular line is y= - $\frac{1}{2}$ x + $\frac{13}{2}$ .

<h3>Linear equation</h3>

A linear equation o line can be expressed in the form y = mx + b.

where

x and y are coordinates of a point.

m is the slope.

b is the ordinate to the origin and represents the coordinate of the point where the line crosses the y axis.

<h3>Perpendicular line</h3>

Perpendicular lines are lines that intersect at right angles or 90° angles. If you multiply the slopes of two perpendicular lines, you get –1.

<h3>Equation of perpendicular line in this case</h3>

In this case, the line is 2x-y=8. Expressed in the form y = mx + b, you get:

-y=8 - 2x

y= (-2x +8)÷ (-1)

y= 2x -8

If you multiply the slopes of two perpendicular lines, you get –1. In this case, the line has a slope of 2. So:

2× slope perpendicular line= -1

slope perpendicular line= (-1)÷ (2)

<u><em>slope perpendicular line= -</em></u> $\frac{1}{2}$

So, the perpendicular line has a form of: y= - $\frac{1}{2}$ x + b

The line passes through the point (9, 2). Replacing in the expression for perpendicular line:

2= (- $\frac{1}{2}$ )× 9 + b

2= - $\frac{9}{2}$ + b

2+ $\frac{9}{2}$ = b

<u><em /></u> $\frac{13}{2}$ <u><em>= b</em></u>

Finally, the equation of of perpendicular line is y= - $\frac{1}{2}$ x + $\frac{13}{2}$ .

Learn more about perpendicular line:

brainly.com/question/7197064

brainly.com/question/11470863

brainly.com/question/7280013

#SPJ1

6 0

2 years ago

Help with number 6 pls i’ll give brainliest

GarryVolchara [31]

Answer:

D. No solution because the lines are parallel

Step-by-step explanation:

Hope this helps you :)

7 0

3 years ago

Y''+Y'+Y=1<br> solve ordinary differential equation

taurus [48]

Answer:

y(t) = c₁ e^(-1/2 t) cos(√3/2 t) + c₂ e^(-1/2 t) sin(√3/2 t) + 1

Step-by-step explanation:

y" + y' + y = 1

This is a second order nonhomogenous differential equation with constant coefficients.

First, find the roots of the complementary solution.

y" + y' + y = 0

r² + r + 1 = 0

r = [ -1 ± √(1² − 4(1)(1)) ] / 2(1)

r = [ -1 ± √(1 − 4) ] / 2

r = -1/2 ± i√3/2

These roots are complex, so the complementary solution is:

y = c₁ e^(-1/2 t) cos(√3/2 t) + c₂ e^(-1/2 t) sin(√3/2 t)

Next, assume the particular solution has the form of the right hand side of the differential equation. In this case, a constant.

y = c

Plug this into the differential equation and use undetermined coefficients to solve:

y" + y' + y = 1

0 + 0 + c = 1

c = 1

So the total solution is:

y(t) = c₁ e^(-1/2 t) cos(√3/2 t) + c₂ e^(-1/2 t) sin(√3/2 t) + 1

To solve for c₁ and c₂, you need to be given initial conditions.

5 0

3 years ago