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timama [110]
2 years ago
5

There are 3 consecutive odd integers that have a sum of 9.

Mathematics
1 answer:
Zolol [24]2 years ago
3 0

Answer:

1+3+5

Step-by-step explanation:

I think

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For each of these lists of integers, provide a simple formula orrule that generates the terms of an integer sequence that begins
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Answer:

The next three terms for each are: a) 123, 146, 171; b) 47,51,55; c) 10000,10001, 10010; d)8,8,8; f)654729075,13749310575,316234142225; g)0,0,0

Step-by-step explanation:

In a) the last number +(2i+1) in which i is the number of terms=1,2,3...

b) n+4, for any last number, you add 4

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d) n=sum of 2 previous different numbers. The frequency is given by 2i-1 in which is is the number of terms i=1,2,3...

e) missing

f) ni+1=n*(2i-1) in which ni+1 is the resulting number, n is the previous number and i is the number of terms=1,2,3...

g) it is 1 for odd numbers and 0 for even numbers. The frequency is given by i+1, in which the number of terms i= 0,1,2,3...

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mylen [45]
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2 years ago
(Pls help me ASAP i will give brainliest!! Also, pls write at least 3 sentences to explain your reasoning :) )
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Answer:

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Step-by-step explanation:

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Answer:

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Answer:

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