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ollegr [7]
3 years ago
6

AB Complementary SinA = 4/5 find Cos b​

Mathematics
1 answer:
Dmitry [639]3 years ago
6 0

Answer:

cos\:b = \frac{4}{5}

Step-by-step explanation:

It is given that: a and b are complementary.

\therefore a + b = 90\degree\\\\\therefore a = 90\degree - b\\\\Assuming\: sin \: ratio \: on\: both\: sides\\\\sin\:a = sin(90\degree - b)\\\\\therefore \frac{4}{5} = sin(90\degree - b)...(\because sin\:a = \frac{4}{5})\\\therefore \frac{4}{5} =cos\:b...\{\because sin(90\degree - \theta) = cos\: \theta\} \\\\\huge\purple{\boxed{\therefore cos\:b = \frac{4}{5}}}\\

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Find the length of the hypotenuse
denpristay [2]

Answer: The answer is “10cm”

Step-by-step explanation: To get to this answer we first need to know the formula for find the hypotenuse which is a^2 + b^2 = c^2. A and B are the two sides in this case a and b are 8 cm and 6 cm. Then you plug in the values into the equation, it looks like this 8^2 + 6^ = c^2 once you solve you get 64 + 36 = c. When you add 64 and 36 you get 100 but their is one more step. You must find the square root of 100 which is 10. So your answer for the hypotenuse is “10cm”

Have a nice day!

4 0
2 years ago
The midpoint of AB is M (2,0). If the coordinates of A are, (-3, 3), what are the coordinates of B?​
gregori [183]

Given:

M is the midpoint of AB.

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To find:

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Solution:

Midpoint formula:

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Let the coordinates of point B are (a,b). Then, using the midpoint formula, we get

(2,0)=\left(\dfrac{-3+a}{2},\dfrac{3+b}{2}\right)

On comparing both sides, we get

\dfrac{-3+a}{2}=2

-3+a=2\times 2

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And,

\dfrac{3+b}{2}=0

3+b=0

3+b-3=0-3

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Therefore, the coordinates of point B are (7,-3).

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2 years ago
Can a pair of numbers have more than one common factor?
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Step-by-step explanation:

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