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leonid [27]
4 years ago
9

The slope of a line is –2 and its y-intercept is (0, 3). What is the equation of the line that is parallel to the first line and

passes through (2, 2)? A. 2x + y = 6 B. y = –2x + 3 C. 2003-10-03-00-00_files/i0060000.jpg D. y = –2x – 6
Mathematics
1 answer:
Doss [256]4 years ago
4 0

Answer:

The answer is A) 2x + y  = 6

Step-by-step explanation:

Since the first line has a slope of -2, we know that the second does as well. We know this because parallel lines have the same slope. Now we can use that slope along with the point in point-slope form to get the equation.

y - y1 = m(x - x1)

y - 2 = -2(x - 2)

y - 2 = -2x + 4

y = -2x + 6

In this case, to find an equation that is similar, we could put it into standard for.

y = -2x + 6

2x + y = 6

This is answer A

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2 years ago
In 20 years, Finn will be 3 times as old as he is right now. How old is he right now?​
Bumek [7]
I think it is 60 years old?
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1 year ago
Robert went to the grocery store and purchased cans of soup and frozen dinners. each can of soup has 300 mg of sodium and each f
Paraphin [41]

There are 9 cans of soup and 5 cans of frozen dinner.

The variables used for soup and frozen dinner are x and y respectively.

Step-by-step explanation:

Let,

Soup = x

Frozen Dinner = y

According to given statement of sodium;

300x + 500y = 5200 eqn 1

And,

x + y = 14 eqn 2

Multiplying\ equation\ 2\ with\ 300\\300(x+y=14)\\300x+300y=4200\ Eqn 3\\

Subtracting Eqn 3 from Eqn 1;

(300x+500y)-(300x+300y)=5200-4200\\300x+500y-300x-300y=1000\\200y=1000\\y=\frac{1000}{200} \\y=5

Putting value of y in Eqn 1;

300x+500(5)=5200\\300x+2500=5200\\\\Subtracting\ 2500\ from\ both\ sides\ \\300x+2500-2500=5200-2500\\300x=2700\\x=\frac{2700}{300} \\x=9

There are 9 cans of soup and 5 cans of frozen dinner.

The variables used for soup and frozen dinner are x and y respectively.

Keywords: Variables, linear equations, subtraction.

Learn more about linear equations at;

  • brainly.com/question/5047646
  • brainly.com/question/5048216

#LearnwithBrainly

5 0
3 years ago
What are the solutions to the equation (2x – 5)(3x – 1) = 0?
user100 [1]

Answer: x=\frac{5}{2}, x=\frac{1}{3}

Explanation:

The equation is:

(2x-5)(3x-1)=0

The term on the left consists of a product of two different factors: therefore, this product can be zero if either the first term (2x-5) or the second term (3x-1) is equal to zero.

This means that we can solve separately for the two terms:

2x-5=0\\3x-1=0

Solving the first equation:

2x-5=0\\2x=5\\x=\frac{5}{2}

Solving the second equation:

3x-1=0\\3x=1\\x=\frac{1}{3}

8 0
3 years ago
Read 2 more answers
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liq [111]

Answer:

6 and 1/3

Step-by-step explanation:

the only thing gets reduced is the fraction part and 5 and 15 have common numbers in 5 5 goes into 5 one time and 5 goes into 15 3 times. so it's 6 1/3

4 0
3 years ago
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