3m+km= -n-8 solve for m

Please tell me the answer plsss i will be sure to mrk u brainliest for the best answer

Finger [1]

Step-by-step explanation:

2^3 X 3^-4 X 5^2 / (2x5)^2 X 2 X 3^2 X 3^-6

I will simply the expression on the RHS if the bracket first

2^2 X 5^2 X 2 X 3^2 X 3^-6

= 2^3 X 3^-4 X 5^2

So, putting them together

Both sides have th same expression

They cancel out each other

Answer : 1

5 0

3 years ago

Calculate the area of a circle with diameter of 12m

andriy [413]

A≈113.1m²
...........................113.1m²

6 0

4 years ago

A plane flying horizontally at an altitude of "1" mi and a speed of "430" mi/h passes directly over a radar station. Find the ra

Anika [276]

Answer:

The rate at which the distance from the plane to the station is increasing when it is 2 mi away from the station is 372 mi/h.

Step-by-step explanation:

Given information:

A plane flying horizontally at an altitude of "1" mi and a speed of "430" mi/h passes directly over a radar station.

$z=1$

$\frac{dx}{dt}=430$

We need to find the rate at which the distance from the plane to the station is increasing when it is 2 mi away from the station.

$y=2$

According to Pythagoras

$hypotenuse^2=base^2+perpendicular^2$

$y^2=x^2+1^2$

$y^2=x^2+1$ .... (1)

Put z=1 and y=2, to find the value of x.

$2^2=x^2+1^2$

$4=x^2+1$

$4-1=x^2$

$3=x^2$

Taking square root both sides.

$\sqrt{3}=x$

Differentiate equation (1) with respect to t.

$2y\frac{dy}{dt}=2x\frac{dx}{dt}+0$

Divide both sides by 2.

$y\frac{dy}{dt}=x\frac{dx}{dt}$

Put $x=\sqrt{3}$ , y=2, $\frac{dx}{dt}=430$ in the above equation.

$2\frac{dy}{dt}=\sqrt{3}(430)$

Divide both sides by 2.

$\frac{dy}{dt}=\frac{\sqrt{3}(430)}{2}$

$\frac{dy}{dt}=372.390923627$

$\frac{dy}{dt}\approx 372$

Therefore the rate at which the distance from the plane to the station is increasing when it is 2 mi away from the station is 372 mi/h.

6 0

4 years ago

-3(4x+5) please help<br>

Natasha_Volkova [10]

Answer:
-12x-15
explanation:
you multiply -3 by 4x, gives u -12x and then you multiply -3 by 15 which gives you -15
then you put it in an equation
-12x-15

7 0

3 years ago

Bert and Ernie are missing each other and their friend Big Bird They want to meet at Big Bird's nest which is halfway from their

algol [13]

Answer:

The distance between Bert and Ernie's apartments from Big Bird's nest

is 21 miles

Step-by-step explanation:

* Lets change the story problem to an equation to solve the problem

- The information i the story problem is

# The Big Bird's nest is halfway from there apartments

# The distance between Bert's apartment and Big Bird's nest is (5x + 4)

# The distance between Ernie's apartment and Big Bird's nest is (15x - 30)

* Now lets solve

∵ The Big Bird's nest is halfway from there apartments

∴ The distance between Bert's apartment and Big Bird's nest = The

distance between Ernie's apartment and Big Bird's nest

∴ 5x + 4 = 15x - 30

- Collect the variable terms in one side and the numerical terms

in th other side

∴ 15x - 5x = 30 + 4 ⇒ add

∴ 10x = 34

∴ x = 34 ÷ 10 = 3.4

* Now lets find the distance between Bert and Ernie's apartments

from the Big Bird's nest

- We can use any relation to find the distance

∵ The distance = 5x + 4

∵ x = 3.4

∴ The distance = 5(3.4) + 4 = 17 + 4 = 21 miles

You can check the answer by using second equation

∵ The distance = 15x - 30

∵ x = 3.4

∴ The distance = 15(3.4) - 30 = 51 - 30 = 21 miles

4 0

3 years ago