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kolezko [41]
3 years ago
7

What is The number in the middle of a data set

Mathematics
2 answers:
Alinara [238K]3 years ago
8 0
It would be the median of the data set
klasskru [66]3 years ago
3 0
I think its the median

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Which expression is equivalent to √147
Iteru [2.4K]
12 is sq root of 144
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Paul has some money in his wallet, all in $1 bills. He buys a hat and has $6 left, as shown in
igor_vitrenko [27]

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we need to see the model

Step-by-step explanation:

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3 years ago
What is the value of the following expression? <br> 4×[6+(27÷3)+11]
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4 0
3 years ago
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If x+1/x= 3, then prove that m^5+1/m^5= 123
alina1380 [7]

9514 1404 393

Explanation:

We can start with the relations ...

  \displaystyle\left(x+\frac{1}{x}\right)^3=\left(x^3+\frac{1}{x^3}\right)+3\left(x+\frac{1}{x}\right)\\\\\left(x+\frac{1}{x}\right)^5=\left(x^5+\frac{1}{x^5}\right)+5\left(x^3+\frac{1}{x^3}\right)+10\left(x+\frac{1}{x}\right)\\\\\textsf{From these, we can derive ...}\\\\x^5+\frac{1}{x^5}=\left(x+\frac{1}{x}\right)^5-5\left(\left(x+\frac{1}{x}\right)^3-3\left(x+\frac{1}{x}\right)\right)-10\left(x+\frac{1}{x}\right)

  \displaystyle x^5+\frac{1}{x^5}=\left(x+\frac{1}{x}\right)^5-5\left(x+\frac{1}{x}\right)^3+5\left(x+\frac{1}{x}\right)\right)\\\\x^5+\frac{1}{x^5}=3^5 -5(3^3)+5(3)\\\\=((3^2-5)3^2+5)\cdot3=(4\cdot9+5)\cdot3=(41)(3)\\\\=\boxed{123}

7 0
3 years ago
Graph the image of △UVW after a reflection over the line y=-x
aliya0001 [1]

Answer:

9514 1404 393

see attached

Step-by-step explanation:

Reflection over the line x = -1 alters the x-coordinates, but leaves the y-coordinates alone. The image point is as far horizontally from the reflection line as the pre-image point is. Each new x-coordinate is the old one subtracted from twice the x-value of the line of reflection: (x, y) ⇒ (-2-x, y) U(-8, -6) ⇒ U'(6, -6) V(-3, -6) ⇒ V'(1, -6) W(-4, -1) ⇒ W'(2, -1)

4 0
3 years ago
Read 2 more answers
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