Create a recursive formula for this sequence (linear)

Mathematics

1 answer:

svetoff [14.1K]3 years ago

4 0

the answer is 3n-2 please do you get it

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Can you explain to me (detailed) on how to do this problem? I will give you a brainly if you get this right.

7nadin3 [17]

Answer:

60 m^2

Step-by-step explanation:

To solve the area, solve the triangle and rectangle separately.

Solve the rectangle:

Multiply 10 and 4 to get the area of 40 m^2.

Solve the triangle:

Multiply 10 and 4, then divide by 2. The formula for a triangle's area is base*height/2. The area is 20.

Add together:

40+20 = 60 m^2

6 0

3 years ago

Simplify: 39w – 16x9

PtichkaEL [24]

Answer:

39w - 144

Step-by-step explanation:

<em>eZ thats y</em>

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3 years ago

Which system is equivalent to 3x squared - 4y squared = 25 over -6x squared -2y squared = 11

TEA [102]

So we are given the following system:
$3x^2-4y^2=25\\
-6x^2-2y^2=11\\\text{Multiply the second equation by -2:}\\12x^2+4y^2=-22\\\text{Add to the first equation we get:}\\15x^2=3
\text{ therefore }x=\pm \sqrt{ \frac{1}{5} }$
Using the first equation again we get:
$3x^2-4y^2=25\\
3x^2=4y^2+25\\
x^2= \frac{1}{3}(4y^2+25)\\x^2= \frac{1}{3}(4 \frac{1}{5} +25)\\= \frac{43}{5}\\x=\pm \sqrt{ \frac{43}{5} }$

3 0

3 years ago

Match the y-coordinate with the given x-coordinate for the equation y = log10x.

Andrew [12]

The non-algebraic functions are called transcendental functions. This include the logarithmic function. The definition of Logarithmic Function with Base a is as follows:

$For \ x\ \textgreater \ 0, \ a \ \textgreater \ 0, \ and \ a \neq 1 \\ \\ y=log_{a}x \ if \ and \ only \ if \ x=a^{y} \\ \\ Then: \\ \\ f(x)=log_{a}x \\ \\ is \ called \ the \ logarithmic \ function \ with \ base \ a.$

We know that the equations is:

$y=log(10x)$

So let's solve each case:

Case 1

$x=\frac{1}{100} \\ \\ y=log(10(\frac{1}{100})) \\ \\ \therefore y=log(\frac{1}{10}) \\ \\ \therefore y=-1 \\ \\ So: \\ \\ \boxed{\ x=\frac{1}{100}} \ matches \ to \ \boxed{y=-1}$

Case 2

$x=\frac{1}{10} \\ \\ y=log(10(\frac{1}{10})) \\ \\ \therefore y=log(1) \\ \\ \therefore y=0 \\ \\ So: \\ \\ \boxed{\ x=\frac{1}{10}} \ matches \ to \ \boxed{y=0}$