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3 years ago

Explain which method to use in 4x^2-27=0

Mathematics

2 answers:

alukav5142 [94]3 years ago

4 0

Answer:

4x^2 = 27
x^2= 27/4
x= +/- sqrt(27/4)
x=+/- 3*sqrt(3)/(2)

Galina-37 [17]3 years ago

3 0

So if we have 4x^2 - 27 = 0 then by using the square root properties we get:

4x^2 = 27
x^2= 27/4
x= +/- sqrt(27/4)
x=+/- 3*sqrt(3)/(2)

hope this helps! any questions please just ask! Thank you!!

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Given that α and β are the roots of the quadratic equation <img src="https://tex.z-dn.net/?f=2x%5E%7B2%7D%20%2B6x-7%3Dp" id="Tex

siniylev [52]

Answer:

$\large \boxed{\sf \ \ \ p=-11 \ \ \ }$

Step-by-step explanation:

Hello,

$\alpha \text{ and } \beta \text{ are the roots of the following equation}$

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It means that

$2\alpha^2+6\alpha-7=p \\\\2\beta ^2+6\beta -7=p \\\\$

And we know that

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So we got two equations

$2(2\beta)^2+6\cdot 2 \cdot \beta -7=p \\\\8\beta^2+12\beta -7=p\\\\ and \ 2\beta ^2+6\beta -7=p \ So \\\\\\8\beta^2+12\beta -7 = 2\beta ^2+6\beta -7\\\\6\beta^2+6\beta =0\\\\\beta(\beta+1)=0\\\\ \beta =0 \ or \ \beta=-1$

For $\beta =0, \ \ \alpha =0, \ \ p = -7$

For $\beta =-1, \ \ \alpha =-2, \ \ p= 2-6-7=-11, \ p=2*4-12-7=-11$

I assume that we are after two different roots so the solution for p is p=-11

b) $\alpha +2 =-2+2=0 \ and \ \beta+2=-1+2=1$

So a quadratic equation with the expected roots is

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Hope this helps.

Do not hesitate if you need further explanation.

Thank you

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Examples of Fraction: $\frac{1}{2}$ , $\frac{2}{7}$ and $\frac{5}{8}$ .

In the first example, $\frac{1}{2}$ , 1 is the numerator, while 2, is the denominator.

Additional Information

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