3 years ago

Explain which method to use in 4x^2-27=0

Mathematics

2 answers:

alukav5142 [94]3 years ago

4 0

Answer:

4x^2 = 27
x^2= 27/4
x= +/- sqrt(27/4)
x=+/- 3*sqrt(3)/(2)

Galina-37 [17]3 years ago

3 0

So if we have 4x^2 - 27 = 0 then by using the square root properties we get:

4x^2 = 27
x^2= 27/4
x= +/- sqrt(27/4)
x=+/- 3*sqrt(3)/(2)

hope this helps! any questions please just ask! Thank you!!

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