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Gemiola [76]
4 years ago
8

Explain which method to use in 4x^2-27=0

Mathematics
2 answers:
alukav5142 [94]4 years ago
4 0
Answer:

4x^2 = 27
x^2= 27/4
x= +/- sqrt(27/4)
x=+/- 3*sqrt(3)/(2)
Galina-37 [17]4 years ago
3 0
So if we have 4x^2 - 27 = 0 then by using the square root properties we get:

4x^2 = 27
x^2= 27/4
x= +/- sqrt(27/4)
x=+/- 3*sqrt(3)/(2)

hope this helps! any questions please just ask! Thank you!!

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Considering the sum of the internal angles of a triangle, the measures are given as follows:

  • x = 10.09.
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  • Angle B: 66.64º.

<h3>What is the sum of the internal angles of a triangle?</h3>

The sum of the internal angles of a triangle is of 180º.

In general terms, the sum of the internal angles of a polygon of n sides is given by:

S = (n - 2) x 180º.

For a triangle, n = 3, hence S = 180º.

For this problem, the three internal angles of the triangle are given as follows:

7x - 4, 4x, 73.

Hence we can solve for x applying the sum as follows:

7x - 4 + 4x + 73 = 180

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x = 10.09.

Hence:

A = 4x = 4 x 10.09 = 40.36º.

B = 7 x 10.09 - 4 = 66.64º.

More can be learned about the sum of the internal angles of a triangle at brainly.com/question/25215131

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