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GrogVix [38]
2 years ago
10

Put the expressions in order from least to greatest.

Mathematics
1 answer:
Arte-miy333 [17]2 years ago
6 0

Answer:

\frac{11^{4} }{11^{11} } ,\frac{1}{11^{-4} }, 11^{5}*11^{2},  (11^{-3})^{-3}

Step-by-step explanation:

For this, you need to know the rules of exponents:

If the coefficient is the same, you can do things to it (which I will get into)

In this case, all the coefficients are 11, so we don't have to worry about the coefficients being different.

For the first one, you can subtract the denominator exponent by the numerator exponent like so:

11^{4} * 11^{-11} = 11^{-7}\\

(When you multiply, you add the exponents)

Also, the rule is: x^{-y} = \frac{1}{x^{y} } or \frac{1}{x^{-y} } = x^{y}

For the second one, you can use the rule mentioned before:

\frac{1}{11^{-4} } = 11^{4}

For the third one, you want to multiply the exponents (in these kinds of cases, you can multiply the exponent by the exponent)

So:

(11^{-3} )^{-3} = 11^{9}

Finally, the fourth one, you can simply just add the exponents:

11^{5} * 11^{2} = 11^{7}

Then, just order them from least to greatest by their exponents value :)

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I don’t understand this can someone please give me and example on how to do it please?
olga55 [171]
For the first one,

you multiply 5x and -5 to get -25.

Then you move the constant to the right and change the sign to get 3x= -21 +25.

Calculate the sum of -21+25 to get 4.

Divide both sides of the equation by 3 to get x=4/3.

So then your final answer is x=4
——
3


For the second one,

Distribute 7 through the parentheses to get 14x + 14+8=120

The you add 14+8 to get 22. Your equation should be 14x+22=120

Move the constant to the right side and change its sign to get 14x=120-22

Subtract 120-22 to get 98. Now your equation should be 14x=98

Divide both sides of the equation by 14 to get x=7.

Your finial answer for the second one should be x=7.
—————————————————————-
I hope this made sense.
5 0
3 years ago
Evaluate the double integral ∬Ry2x2+y2dA, where R is the region that lies between the circles x2+y2=16 and x2+y2=121, by changin
olga2289 [7]

Answer:

See answer and graph below

Step-by-step explanation:

∬Ry2x2+y2dA

=∫Ry.2x.2+y.2dA

=A(2y+4Ryx)+c

=∫Ry.2x.2+y.2dA

Integral of a constant ∫pdx=px

=(2x+2.2Ryx)A

=A(2y+4Ryx)

=A(2y+4Ryx)+c

The graph of y=A(2y+4Ryx)+c assuming A=1 and c=2

8 0
3 years ago
Can someone please answer this asap (50 Points)<br> Graph the following piecewise function.
kiruha [24]

answer D for the equation

8 0
3 years ago
Read 2 more answers
What’s the answer to this
Vinvika [58]

Answer:

The answer is A

Step-by-step explanation:

7 0
3 years ago
Solve :(use unitary method)
andre [41]

Answer:

a. 8

b. 114

Step-by-step explanation:

a.

36/6 = 48/x

36x = 288

x = 8

b.

12/72 = 19/x

1/6 = 19/x

x = 114

8 0
2 years ago
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