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gavmur [86]
3 years ago
9

How do i add

title="-\frac{3}{10} plus \frac{2}{3 }\\" alt="-\frac{3}{10} plus \frac{2}{3 }\\" align="absmiddle" class="latex-formula">.
Mathematics
1 answer:
antoniya [11.8K]3 years ago
4 0

-\dfrac{3}{10}+\dfrac{2}{3}=\dfrac{2}{3}+\left(-\dfrac{3}{10}\right)=\dfrac{2}{3}-\dfrac{3}{10}\\\\\text{We must find the common denominator.}\\\\Multiples\ of\ 3:0,\ 3,\ 6,\ 9,\ 12,\ 15,\ 18,\ 21,\ 24,\ 27,\ \boxed{30},\ 33,\ 36,...\\\\Multiples\ of\ 10:\ 0,\ 10,\ 20,\ \boxed{30},\ 40,\ 50,\ 60,...\\\\\dfrac{2}{3}=\dfrac{2\cdot10}{3\cdot10}=\dfrac{20}{30}\\\\\dfrac{3}{10}=\dfrac{3\cdot3}{10\cdot3}=\dfrac{9}{30}\\\\\dfrac{2}{3}-\dfrac{3}{10}=\dfrac{20}{30}-\dfrac{9}{30}=\dfrac{20-9}{30}=\dfrac{11}{30}

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Anon25 [30]

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mutiply the bracket by 3

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Given:

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     z                                     c                               zc

  Sum                              a+b+c                          xa+yb+zc

Now, the mean average score on the test is

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Therefore, the mean average score on the test is \dfrac{xa+yb+zc}{a+b+c}.

3 0
3 years ago
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Answer:

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8 0
3 years ago
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