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tamaranim1 [39]
3 years ago
10

Chantel drew a picture of her dog on a piece of paper that is 12 centimeters long. She used a copy machine to enlarge her drawin

g. She used the 115% setting to make each new copy. She then used each new copy to generate the next copy, using the same copier setting.
Enter a recursive formula that will give the length of each new copy.


Possible Answer:

a_1 = 12

a_n=1.15a_n-1


I want to know howto show work
HELPPPPPPPPPPPPPPPPPPPPPPPP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Mathematics
1 answer:
Georgia [21]3 years ago
3 0

Answer:

a(n)=1.15[a(n-1)]

Step-by-step explanation:

we know that

115\%=115/100=1.15

Let

a0 -----> the length of the original copy

<em>The first copy is equal to</em>

a1=1.15(a0)

<em>The second copy is </em>

a2=1.15[1.15(a0)] or a2=1.15[a1]

<em>The third copy is</em>

a3=1.15{1.15[1.15(a0)]} or a3=1.15[a2]

therefore

A recursive formula will be

a(n)=1.15[a(n-1)]

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Arrange the quantities in order from smallest to largest.<br> 2.6 km​, 109,000 mm​, 41.7 hm
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The order of the values using the basic unit of meters from smallest to largest. is: 109000 mm < 2.6 km < 41.7 hm

What are the units of measurement of distance or length?

Distance is the gap between any two points under consideration.

The basic unit for measuring distance is the meter.

There are larger as well as smaller units for measuring length or distance which are based on the unit of meter.

The units are as follows:

millimeter, mm = 0.001 m

centimeter, cm = 0.01 m

decimeters, dm = 0.1 m

meter, m = 1 m

kilometer, km = 1000 m

hectometer, hm = 100 m

Now to compare the given quantities making the units same as two quantities can only be compared only when there units are same :

Considering the given values;

2.6 km = 2600 m

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Prime factorization to find the lcm and gcf of 86,42
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According to an NRF survey conducted by BIGresearch, the average family spends about $237 on electronics (computers, cell phones
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Answer:

7.64% probability that they spend less than $160 on back-to-college electronics

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 237, \sigma = 54

Probability that they spend less than $160 on back-to-college electronics

This is the pvalue of Z when X = 160. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{160 - 237}{54}

Z = -1.43

Z = -1.43 has a pvalue of 0.0763

7.64% probability that they spend less than $160 on back-to-college electronics

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