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3 years ago

484,343 rounded to the nearest thousand

Mathematics

2 answers:

Semmy [17]3 years ago

3 0

Answer:

484,000

Step-by-step explanation:

The hundreds place is less than 5 so you round down.

OverLord2011 [107]3 years ago

3 0

Answer:

484,000

Step-by-step explanation:

Since we have to round to the nearest thousand, which is 4,000, we have to look at the hundred place. It is 3, so we have to round down (Stay the same).

So, the answer is 484,000

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Thomas wrote the expanded form of (5_2^4 below.

soldier1979 [14.2K]

This is what I got, hope it helps (I used a calculator for this on Google)
Expanded Notation Form:

5

Expanded Factors Form:

5 ×

1

Expanded Exponential Form:

5 × 100

7 0

3 years ago

Read 2 more answers

What is the circle's circumference? The diameter of a circle is 6 millimetres.

dolphi86 [110]

Answer:

C = 6pi or approximately 18.84 mm

Step-by-step explanation:

The circumference of a circle is

C = pi *d

C = pi *6

We can approximate pi by 3.14

C = 3.14*6

C =18.84

6 0

3 years ago

A farmer has a field in the shape of a triangle. The farmer has asked the manufacturing class at your school to build a metal fe

Finger [1]

Answer:

Fencing required = 1586 m

Step-by-step explanation:

The given statements can be thought of a triangle $\triangle ABC$ as shown in the diagram attached.

A be the 1st vertex, B be the 2nd vertex and C be the 3rd vertex.

Distance between 1st and 2nd vertex, AB = 435 m

Distance between 2nd and 3rd vertex, AC = 656 m

$\angle A =49^\circ$

To find:

Fencing required for the triangular field.

Solution:

Here, we know two sides of a triangle and the angle between them.

To find the fencing or perimeter of the triangle, we need the third side.

Let us use Cosine Rule to find the third side.

Formula for cosine rule:

$cos A = \dfrac{b^{2}+c^{2}-a^{2}}{2bc}$

Where

a is the side opposite to $\angle A$

b is the side opposite to $\angle B$

c is the side opposite to $\angle C$

$\Rightarrow cos 49^\circ = \dfrac{656^{2}+435^{2}-BC^{2}}{2\times 435\times 656}\\\Rightarrow BC^2 = 430336+189225-2 (435)(656)cos49^\circ\\\Rightarrow BC^2 = 430336+189225-570720\times cos49^\circ\\\Rightarrow BC^2 =619561-570720\times cos49^\circ\\\Rightarrow BC \approx 495\ m$

Perimeter of the triangle = Sum of three sides = AB + BC + AC

Perimeter of the triangle = 435 + 495 + 656 = 1586 m

Fencing required = 1586 m

4 0

3 years ago

A standard oil drum is a cylinder with a volume of approximately 218.276 liters (or 0.218276 cubic meters). The cost of producin

Arte-miy333 [17]

Answer:

r = 2,85 feet

h = 8,56 feet

Step-by-step explanation:

Area of two circular caps (m ^(2)) : 2* pi* r^(2) (where r is the radius of circular cap) Area of wall (m ^(2)) is 2*pi*r*h (where h is the height of drum)

V= pi*r^(2)*h so h=V/pi*r^(2) (1)

Cost in $:

Cost of wall 25 $/m^(2) plus 10% for manufacturing so:

C(w) = 27,5*2*pi*r*h $/square feet

Cost of (both top and bottom cap) = 2*40,97*pi* r^(2) so:

C(caps) = 257,29* r^(2) $/squaer feet

Total cost of cylnder = cost of wall + cost of caps

Total cost f cylinder: F(c)= 55*pi*r*h+257,29* r^(2)

F(c) = 172,7*r*h + 257,29*r^(2) F(c) is F(r)

Since from (1) we have h=218,276/pi*r^(2)

F(r) = (172,7)*r*(69,514)/r^(2) +257,29*r^(2) F(c) = 12005/r + 257,29*r^(2)

Taken the first dervative

F´(r)= -12005*(1)/r^(2) +2*257,29*r F´(r) = -12005*(1)/r^(2) +514,58*r

f F´(r) = 0 -12005*(1)/r^(2) + 514,58*r =0

-120005 + 514,58*^(3) = 0 514,58*^(3) = 12005 r =cubic root (23,32)

r = 2,85 ft

if we replace this value en F(r) we can see F(r) tend to infinite both when r tend to 0 and when r tends to infnite so there is a minimun for the functon

r = 2,85 ft and h = 8,56 ft

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3 years ago

11x + 4y = 32 x = -2y - 2

borishaifa [10]

The answer is y= -x/2 -1 solving for the Y

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