If you can rewrite the formula as (x-a)² + (y-b)² = r², the center is at (a,b) and the radius is r.
If you work out this equation, and map it to the original, you will find that the +4x term hints that a = 2 (double product) and -12y hints that b=-6, and r=6.
So, the formula can be written as (x+2)² + (y-6)² = 6² and the center is at (-2,6) and the radius is 6.
Answer:
Step-by-step explanation:
(jk^-2/j^-1k^-3)^3
(-2)(-1)^-2
------------- ^3
(-2)^-1(-1)^-3
switch negative exponenst to other side
(-2)(-2)(-1)^3
__________
(-1)^2
4(-1)
-----
1
= -4
REMEMBER all to the 3rd power!
(-4)^3
-64
Answer:
−(7p+6)−2(−1−2p) = - 3p - 4
Step-by-step explanation:
−(7p+6)−2(−1−2p) = -7p - 6 + 2 + 4p
= (-7p + 4p) + (2 - 6)
= -(7p - 4p) - (6 - 2)
= - 3p - 4
You draw a straight line and then put your number on the line. If you have to find a negative number, you can just go below zero. Positive numbers on a number line are always above zero. Hope this helps!
Answer:
no mode , 6 , 6.24
Step-by-step explanation:
