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scoray [572]
3 years ago
10

Use the quadratic formula to solve the quadratic equation. SHOW ALL WORK. 2 −8+41 = 0

Mathematics
1 answer:
horsena [70]3 years ago
5 0

Answer:

Solving the equation x^2-8x+41=0 using quadratic formula we get x=4+5i \ or \ x=4-5i

Step-by-step explanation:

We need to solve the equation x^2-8x+41=0 using quadratic formula.

The quadratic formula is:

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

where a=1, b=-8 and c=41

Putting values in formula and finding x

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$\\$x=\frac{-(-8)\pm\sqrt{(-8)^2-4(1)(41)}}{2(1)}$\\$x=\frac{8\pm\sqrt{64-164}}{2}$\\$x=\frac{8\pm\sqrt{-100}}{2}$\\We \ know \ \sqrt{-1}=i\\x=\frac{8\pm10i}{2}\\x=\frac{8+10i}{2} \ or \ x=\frac{8-10i}{2}\\x=4+5i \ or \ x=4-5i

So, Solving the equation x^2-8x+41=0 using quadratic formula we get x=4+5i \ or \ x=4-5i

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Answer:

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Step-by-step explanation:

A product means multiplication, and you need to multiply x by 5 in order to make the product have a factor of 5.

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Answer:

(-3, -4)

Step-by-step explanation:

Handy fact: the average of two numbers is exactly halfway between them.

To find the midpoint, average the x-coordinates; average the y-coordinates.

(1 + -7)/2 = -6/2 = -3

(-8 + 0)/2 = -8/2 = -4

The midpoint is (-3, -4).

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3 years ago
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Step-by-step explanation:

  • <em>-x-4=</em><em>4</em><em>x</em><em>-</em><em>5</em><em>4</em>

Adding x on both sides, we get

  • <em>-x-4+</em><em>x=</em><em>4</em><em>x</em><em>-</em><em>5</em><em>4</em><em>+</em><em>x</em>
  • <em>-</em><em>4</em><em>=</em><em>5</em><em>x</em><em>-</em><em>5</em><em>4</em>

Adding 54 on both sides, we get

  • <em>-</em><em>4</em><em>+</em><em>5</em><em>4</em><em>=</em><em>5</em><em>x</em><em>-</em><em>5</em><em>4</em><em>+</em><em>5</em><em>4</em>
  • <em>5</em><em>0</em><em>=</em><em>5</em><em>x</em>

Dividing both sides by 5, we get

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<em>Hence,</em><em> </em><em>the </em><em>value</em><em> of</em><em> x</em><em> </em><em>is</em><em> </em><em>1</em><em>0</em><em>.</em>

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Step-by-step explanation:

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