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scoray [572]
3 years ago
10

Use the quadratic formula to solve the quadratic equation. SHOW ALL WORK. 2 −8+41 = 0

Mathematics
1 answer:
horsena [70]3 years ago
5 0

Answer:

Solving the equation x^2-8x+41=0 using quadratic formula we get x=4+5i \ or \ x=4-5i

Step-by-step explanation:

We need to solve the equation x^2-8x+41=0 using quadratic formula.

The quadratic formula is:

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

where a=1, b=-8 and c=41

Putting values in formula and finding x

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$\\$x=\frac{-(-8)\pm\sqrt{(-8)^2-4(1)(41)}}{2(1)}$\\$x=\frac{8\pm\sqrt{64-164}}{2}$\\$x=\frac{8\pm\sqrt{-100}}{2}$\\We \ know \ \sqrt{-1}=i\\x=\frac{8\pm10i}{2}\\x=\frac{8+10i}{2} \ or \ x=\frac{8-10i}{2}\\x=4+5i \ or \ x=4-5i

So, Solving the equation x^2-8x+41=0 using quadratic formula we get x=4+5i \ or \ x=4-5i

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<span>The inequality |2x − 6| less than or equal to 10 can be expressed as two form like this to get two value of x
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