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scoray [572]
2 years ago
10

Use the quadratic formula to solve the quadratic equation. SHOW ALL WORK. 2 −8+41 = 0

Mathematics
1 answer:
horsena [70]2 years ago
5 0

Answer:

Solving the equation x^2-8x+41=0 using quadratic formula we get x=4+5i \ or \ x=4-5i

Step-by-step explanation:

We need to solve the equation x^2-8x+41=0 using quadratic formula.

The quadratic formula is:

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

where a=1, b=-8 and c=41

Putting values in formula and finding x

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$\\$x=\frac{-(-8)\pm\sqrt{(-8)^2-4(1)(41)}}{2(1)}$\\$x=\frac{8\pm\sqrt{64-164}}{2}$\\$x=\frac{8\pm\sqrt{-100}}{2}$\\We \ know \ \sqrt{-1}=i\\x=\frac{8\pm10i}{2}\\x=\frac{8+10i}{2} \ or \ x=\frac{8-10i}{2}\\x=4+5i \ or \ x=4-5i

So, Solving the equation x^2-8x+41=0 using quadratic formula we get x=4+5i \ or \ x=4-5i

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A bus travels 12 miles in 20 minutes at this rate how many miles does the bus travel in 60 minutes
Dovator [93]

Answer:

If I'm answering this right, the bus should have travel 36 miles in 60 minutes.

If it takes 20 minutes to get to 12 miles then for every twenty minutes you would just add 12 miles.

3 0
3 years ago
What is the sum of 7 2/6 + 2 1/4
vovikov84 [41]

Answer:

115/12

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
A golfer takes two putts to get the ball into the hole. The first putt rolls the ball 10.3 feet in the northwest direction and t
creativ13 [48]

Let's put this on the usual Cartesian grid just so we can talk about it without drawing a picture.  We'll use map conventions, right is east, up is north.

The ball starts at (0,0).   10.3 feet northwest means we have an isosceles right triangle whose diagonal is 10.3 feet.  It's isosceles because northwest means equal parts north and west.   

The sides of these triangles are in ratio 1:1:\sqrt{2} so the coordinates after the first putt are

(- 10.3 / \sqrt{2}, 10.3 / \sqrt{2})

The negative sign indicates west, which doesn't really matter for this problem.  The distance from the origin to this point is 10.3 as required.

Now a second putt of 3.8 feet north puts us at
 
(- 10.3 / \sqrt{2}, 10.3 / \sqrt{2} + 3.8)

The squared distance to the origin is exactly

d^2 = 10.3^2/2 + (10.3 / \sqrt{2} + 3.8)^2

A little calculator work tells us

d \approx 13.2621

Third choice.



3 0
3 years ago
Find the equation of the line shown.
Luda [366]

Answer:

y = -x + 9

Step-by-step explanation:

✔️Find the slope using (9, 0) and (7, 2):

slope (m) = \frac{y_2 - y_1}{x_2 - x_1} = \frac{2 - 0}{7 - 9} = \frac{2}{-2} = -1

Slope (m) = -1

✔️Find the y-intercept (b):

The line intercepts the y-axis when y = 9. Therefore, y-intercept (b) = 9

✔️Substitute m = -1 and b = 9 into y = mx + b

Thus,

y = -1(x) + 9

y = -x + 9

5 0
3 years ago
Find the area of the regular trapezoid. The figure is not drawn to scale. The top side is 4, the bottom side is 7, and both side
svp [43]
A regular trapezoid is shown in the picture attached.

We know that:
DC = minor base = 4
AB = major base = 7
AD = BC = lateral sides or legs = 5

Since the two legs have the same length, the trapezoid is isosceles and we can calculate AH by the formula:

AH = (AB - DC) ÷ 2
      = (7 - 5) ÷ 2
      = 2 ÷ 2
      = 1

Now, we can apply the Pythagorean theorem in order to calculate DH:
DH = √(AD² - AH²) 
      = √(5² - 1²)
      = √(25 - 1)
      = √24
      = 2√6

Last, we have all the information needed in order to calculate the area by the formula:

A =  \frac{(AB + CD)DH}{2}

A = (7 + 5) × 2√6 ÷ 2
   = 12√6

The area of the regular trapezoid is 12√6 square units.

7 0
3 years ago
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