Ask question

Ask question

All categories

3 years ago

6

An irregular figure was broken into a triangle and rectangle. The area of the triangle is in2. The area of the rectangle is in2.

The area of the irregular figure is in2.

1 answer:

Zanzabum3 years ago

5 0

Answer:

the anser is 24,32,56

Step-by-step explanation:

i did it got it wrong and then it gave me the right anser witch is that

You might be interested in

Income Taxes: Mastery Test

Margarita [4]

Answer:

1. tax deductions 2. the one that isn't amount of tax owed

Step-by-step explanation:

got the first part right and reviewed it on plato to see that The amount of tax owed is not the right answer.

4 0

2 years ago

You mix 1/2 cup of red paint for every 1/4 cup of blue paint to make 12 cups of

Serhud [2]

4 cups of blue paint and 8 cups of red paint

explanation

to pour one cup of blue paint, two cups of red paint has to be poured.
since when you add both those it adds to 3
so multiply each by 4 to get 4 cups of blue paint and 8 cups of red paint

3 0

2 years ago

Solve for a in the figure shown.

aleksandrvk [35]

Answer: 58 is the answer

hope this help and here my steps use a mark or a pin

and line it with the line if it's wrong sorry for the wrong

answer

7 0

2 years ago

Read 2 more answers

Lori creates the following design for a T-shirt.

kakasveta [241]

<u>Solution-</u>

From the figure,

AE = 2.4

EB = 2.8

BC = 11.7

Area of rectangle 1 = 8.68 sq.in

$\Rightarrow FH \times HI=8.68$

$\Rightarrow EB \times HI=8.68$ (∵ sides of the rectangle 2)

$\Rightarrow 2.8 \times HI=8.68$

$\Rightarrow HI=3.1$

Area of Triangle 1 = 6.48 sq.in

$\Rightarrow \frac{1}{2}\times AE \times EG= 6.48$

$\Rightarrow \frac{1}{2}\times AE \times (EF+FG)= 6.48$

$\Rightarrow \frac{1}{2}\times AE \times (EF+HI)= 6.48$ (∵ sides of the rectangle 1)

$\Rightarrow EF+3.1= 5.4$

$\Rightarrow EF=2.3$

$\Rightarrow BH=2.3$ (∵ sides of the rectangle 2)

$BC = BH+HI+IC$

$\Rightarrow 11.7= 2.3+3.1+IC$

$\Rightarrow IC=6.3$

The area of Rectangle 2,

$=EB\times BH =2.8\times 2.3=6.44\ sq.in$

The area of Triangle 2,

$\frac{1}{2}\times GI \times IC=\frac{1}{2}\times EB \times IC=\frac{1}{2}\times 2.8 \times 6.3=8.82\ sq.in$

The area of the whole figure = Area of Triangle 1 + Area of rectangle 1 + Area of Triangle 2 + Area of rectangle 2

= 6.48+8.68+8.82+6.44=30.42 sq.in

6 0

3 years ago

PLEASE HELP I GIVE THANKS

dezoksy [38]

For cylinders to be similar, the ratio between their height and radius must be equal.Our cylinder's ratio is :
$\frac { length }{ radius } =\frac { 15 }{ 3 } \\ =5$

The only cylinder with same ratio is the one at the choice B.

$\frac { length }{ radius } \frac { 25 }{ 5 } =5$

6 0

3 years ago