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3 years ago

Sinx•Tanx•Cotx•Cscx =

Mathematics

1 answer:

nekit [7.7K]3 years ago

8 0

Answer:

the answer of this question is " 1 "

Step-by-step explanation:

tanx = sinx/cosx

cotx = cosx/sinx

cscx = 1/sinx

after putting them all in the given equation

sinx.(sinx/cosx).(cosx/sinx).(1/sinx)

they all are canceled as all are being multiplied with their reciprocals so answer is " 1 "

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3 years ago

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3 years ago

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3 years ago

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Firdavs [7]

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4 years ago

A bakery wants to determine how many trays of doughnuts it should prepare each day. Demand is normal with a mean of 5 trays and

Alexeev081 [22]

Answer:

4 trays should he prepared, if the owner wants a service level of at least 95%.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 5

Standard Deviation, σ = 1

We are given that the distribution of demand score is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

P(X > x) = 0.95

We have to find the value of x such that the probability is 0.95

P(X > x)

$P( X > x) = P( z > \displaystyle\frac{x - 5}{1})=0.95$

$= 1 -P( z \leq \displaystyle\frac{x - 5}{1})=0.95$

$=P( z \leq \displaystyle\frac{x - 5}{1})=0.05$

Calculation the value from standard normal z table, we have,

$\displaystyle\frac{x - 5}{1} = -1.645\\x = 3.355 \approx 4$

Hence, 4 trays should he prepared, if the owner wants a service level of at least 95%.

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3 years ago