Look at the figure. Name the postulate or theorem you can use to prove the triangles congruent.

Mathematics

1 answer:

Alona [7]3 years ago

4 0

Answer:

the last one I think sorry if its incorrect

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Put these fractions in order of size smallest to largest 1/4 a) 1/2 b) 1/3 c)

Serjik [45]

Answer:

smallest to largest would be 1/4, 1/3, 1/2

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

6. In Diagram 1, NPQRSTUV is a regular octagon. NVW and STW are straight lines.

Sveta_85 [38]

Answer:

A. 37.5°

Step-by-step explanation:

∠SPT can be considered an inscribed angle in the circumcircle. In that circle, arc ST would have a measure of 360°/8 = 45°. Angle y° is half that measure, so is 22.5°.

The external angles of a regular octagon are 360°/8 = 45°, so that is the measure of angles UTW and UVW. It is also the amount by which reflex angle TUV exceeds 180°.

The sum of the interior angles of quadrilateral TUVW is ...

45° +225° +45° +3x° = 360°

Then 3x° = 45° and x° = 15°.

Then the sum of interest is ...

x° + y° = 15° + 22.5° = 37.5°

3 0

3 years ago

-3,6,-9,12,-15 which of the following represents the general term for the sequence give?

Mademuasel [1]

The general term for the sequence $a_{n}=(-1)^{n} 3 n$

<h3><u>Solution:</u></h3>

Given sequence is -3, 6, -9, 12, -15

We have to find the general term of sequence

The terms in the sequence are found out by using the recursive definition:

$a_{n}=(-1)^{n} 3 n$

Let us use this definition to find out the terms and check if it matches our given sequence

$\begin{array}{l}{\text { For } n=1:-(-1)^{n} 3 n=(-1)^{1} \times 3 \times 1=-3} \\\\ {\text { For } n=2:-(-1)^{n} 3 n=(-1)^{2} \times 3 \times 2=1 \times 6=6} \\\\ {\text { For } n=3:-(-1)^{n} 3 n=(-1)^{3} \times 3 \times 3=-1 \times 9=-9} \\\\ {\text { For } n=4:-(-1)^{n} 3 n=(-1)^{4} \times 3 \times 4=1 \times 12=12} \\\\ {\text { For } n=5:-(-1)^{n} 3 n=(-1)^{5} \times 3 \times 5=-1 \times 15=-15}\end{array}$