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denpristay [2]
3 years ago
6

Look at the figure. Name the postulate or theorem you can use to prove the triangles congruent.

Mathematics
1 answer:
Alona [7]3 years ago
4 0

Answer:

the last one I think sorry if its incorrect

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Please help me <br>solve 3x+1/2=3/8+x​
gavmur [86]

Answer:

x= -\frac{1}{32}

Step-by-step explanation:

First move the x on the right side the the left side. Now your equation is

2x+\frac{1}{2}=\frac{3}{8} Next move 1/2 to the right side. Now your equation is 4x=\frac{-1}{8}. Next divide both sides by 4 to isolate "x." Now your equation is x= -\frac{1}{32}

Hope this helped and have a great day.

(brainliest please)

6 0
3 years ago
100 POINTS
gulaghasi [49]
C. Alternate interior angles are formed by a transverse line intersecting two parallel lines . They are located between the two parallel lines but on opposite sides of the transverse line
5 0
2 years ago
Read 2 more answers
Can anyone tell me what point I plot these two at pls
zhuklara [117]

Answer:

x^{2} +y^{2}=25

x^{2} +y^{2}=5

<em>Radius: 5</em>

<em>Radius: </em>\sqrt{5}

Step-by-step explanation:

(see images below)

Hope this helped!

~<u>rere</u>

4 0
2 years ago
2 Probability and Stats questions!!
mart [117]
 1) To find the confidence interval 
the sample mean x = 38     σ = 9; n = 85;
The confidence level is 95% (CL = 0.95) <span>CL = 0.95
so α = 1 – CL = 0.05   
</span><span>α/2 = 0.025   </span>Z(α/2) = z0.025  
The area to the right of Z0.025 is 0.025 and the area to the left of Z0.025 is 1 – 0.025 = 0.975
Z(α/2) = z0.025 = 1.645 This can be found using a computer, or using a probability table for the standard normal distribution.
<span>EBM = (1.645)*(9)/(85^0.5)=1.6058</span> x - EBM = 38 – 1.6058 = 36.3941 <span> x + EBM = 38 + 1.6058 = 39.6058
</span>The 95% confidence interval is (36.3941, 39.6058).
The answer is the letter D
<span>The value of 40.2 is <span>within the 95% confidence interval for the mean of the sample

</span></span>2) To find the confidence interval  <span>
<span>the sample mean x = </span>76     σ = 20; n = 102; </span><span>
The confidence level is 95% (CL = 0.95) CL = 0.95 
so α = 1 – CL = 0.05   
α/2 = 0.025   Z(α/2) = z0.025 
The area to the right of Z0.025 is 0.025 and the area to the left of Z0.025 is 1 – 0.025 = 0.975 
Z(α/2) = z0.025 = 1.645 This can be found using a computer, or using a probability table for the standard normal distribution.
EBM = (1.645)*(20)/(102^0.5)=3.2575 x - EBM = 76 – 3.2575 = 72.7424 </span>  x + EBM = 76 + 3.2575 = 79.2575 <span> 
The 95% confidence interval is (</span>72.7424 ,79.2575).<span>
The answer is the letter </span>A and the letter D<span>
The value of 71.8 and 79.8 <span> are </span> outside<span> the 95% confidence interval for the mean of the sample</span></span>
5 0
3 years ago
What is the expanded form of the series represented below?
34kurt
I think the answer is B
4 0
3 years ago
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