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Sunny_sXe [5.5K]

3 years ago

13

The given graph represents the function f(x) = 2(5)x. How will the appearance of the graph change if the a value in the function

is decreased, but remains greater than 0?

2 answers:

Naddika [18.5K]3 years ago

6 0

Answer:

answer is C

Step-by-step explanation:

castortr0y [4]3 years ago

4 0

The answer is C: "The graph will show an initial value that is lower on the y-axis."

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Okay so- im really stuck (help is well appreciated)

Minchanka [31]

Answer:

Step-by-step explanation:

The equation is x<= 5.

So 5 and all the numbers less than 5 would be an answer for x.

So you would put a closed dot on 5, because x can equal 5. Then put a line pointing right to all the numbers less than 5.

7 0

2 years ago

Read 2 more answers

Han has 10 cubes, each 5 inches on a side. A) Find the total volume of Han’s cubes. Express your answer as an expression using a

g100num [7]

Answer:

A) Vol_10_cubes = 2*(5^4) inch^3

B) Area_10_cubes = (2^2)*3*(5^3) inch^2

Step-by-step explanation:

A)The volume of a cube, as all sides are equal:

Vol_cube = (side)^3

side = 5 inches

Vol_cube = 5^3 inch^3

Since we have 10 cubes

10 = 2*5

Vol_10_cubes = 2*(5^4) inch^3

B) A cube has six faces, each with area equal to its squared side

Area_cube = 6*(side)^2

Area_cube = 6*(5)^2 inch^2

Area_10_cubes = 2*5*6*(5)^2 inch^2

Area_10_cubes = (2^2)*3*(5)^3 inch^2

8 0

3 years ago

Match the graph to the related table.

lana66690 [7]

Answer:

Option C

Step-by-step explanation:

Option c is right answer

3 0

2 years ago

Read 2 more answers

From a practice assignment:<br>solve the following differential equation given initial conditions

hodyreva [135]

If $y' = e^y \sin(x)$ and $y(-\pi)=0$ , separate variables in the differential equation to get

$e^{-y} \, dy = \sin(x) \, dx$

Integrate both sides:

$\displaystyle \int e^{-y} \, dy = \int \sin(x) \, dx \implies -e^{-y} = -\cos(x) + C$

Use the initial condition to solve for $C$ :

$-e^{-0} = -\cos(-\pi) + C \implies -1 = 1 + C \implies C = -2$

Then the particular solution to the initial value problem is

$-e^{-y} = -\cos(x) - 2 \implies e^{-y} = \cos(x) + 2$

(A)

4 0

1 year ago

Find x so that (x,-14) is a solution to 2x+3y=12

Monica [59]

Answer:

27

Question:

Find $x$ so that $(x,-14)$ is a solution to $2x+3y=12$ .

Step-by-step explanation:

So we are asked to replace $y$ with -14 and solve for $x$ in the equation:

$2x+3y=12$ .

$2x+3y=12$ with $y=-14$ :

$2x+3(-14)=12$

$2x-42=12$

Add 42 on both sides:

$2x=54$

Divide both sides by 2:

$x=27$ .

So the $x$ -coordinate that corresponding to $y=-14$ is $27$ .

Verify that:

$(27,-14)$ is a point satisfying $2x+3y=12$ .

Replace $x$ with 27 and $y$ with -14:

$2(27)+3(-14)=12$

$54+-42=12$

$12=12$ is true so our work must be right.

3 0

3 years ago