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Sunny_sXe [5.5K]
3 years ago
13

The given graph represents the function f(x) = 2(5)x. How will the appearance of the graph change if the a value in the function

is decreased, but remains greater than 0?
Mathematics
2 answers:
Naddika [18.5K]3 years ago
6 0

Answer:

answer is C

Step-by-step explanation:



castortr0y [4]3 years ago
4 0

The answer is C:  "The graph will show an initial value that is lower on the y-axis."

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Round 1400 to the nearest 10
anygoal [31]

Answer:

1395 is the lower bound because 1395 rounded to the nearest 10 is 1400 but 1394 rounded to the nearest 10 is 1390.

Step-by-step explanation:


7 0
3 years ago
Which of the following mathematical statements shows "the quotient of a number and six is eight”?
rosijanka [135]
N ÷ 6 = 8
hope this helps good luck! =]
6 0
3 years ago
HELP PLSS !!! Will mark as brainiest
Natasha_Volkova [10]

Answer:

1709.92cm^3

Step-by-step explanation:

V=\pi r^2h=\pi *3^2*7=197.92cm^2 (cylinder)

V=whl=14*9*12=1512cm^3(rectangular prism)

197.92+1512=1709.92cm^3(whole shape)

5 0
3 years ago
Question
ololo11 [35]

Answer:

correct experiment: viral culture test

Trial: (RCT) random control trial

It causes mild sickness or death

6 0
2 years ago
A group of 100 people is divided into 2 teams with 45 people in team A and 55 people in team B.
Zepler [3.9K]
Team A) 45 people
Team B) 55 people

A)There are two ways to solve this problem, finding the number of combinations possible for Team B, or the number of combinations possible for Team A. 
Team A
It's a given that 20 mathematicians are on team A, which leavs the other 25 people for team A to be chosen from a pool of 80 (100- 20 mathletes)
80-C-25 = 80! / (25!/(80-25)!) =<span>363,413,731,121,503,794,368
</span>or 3.63 x 10^20
Solving using Team B
Same concept, but choosing 55 from a pool of 80 (mathletes excluded)
80-C-25 = 80! / (55!(80-55!) = 363,413,731,121,503,794,368
or 3.63 x 10^20

As you can, we get the same answer for both. 

B)
If none of the mathematicians are on team A, then we exclude the 20 and choose 45:
80-C-45 = 80! / (45!(80-45)!) = <span>5,790,061,984,745,3606,481,440
or 5.79 x 10^22

Note that, if you solve from the perspective of Team B (80-C-35), you get the same answer</span>
7 0
3 years ago
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