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vredina [299]
2 years ago
6

Carl is boarding a plane. He has 222 checked bags of equal weight and a backpack that weighs 4 \text{ kg}4 kg4, start text, spac

e, k, g, end text. The total weight of Carl's baggage is 35 \text{ kg}35 kg35, start text, space, k, g, end text.
Mathematics
1 answer:
Finger [1]2 years ago
4 0

Answer:

khanacademy is always watching be aware

Step-by-step explanation:

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4<br> Select the correct answer.<br> Which of these mappings is a function?
melomori [17]

Answer:

? i need a better explanation for ur questoin

Step-by-step explanation:

3 0
3 years ago
I WILL GIVE BRAINLIEST TO WHOEVER ANSWERS FIRST! A circle has a diameter AB, and its center is at (-3, 3). Point A is at (1/2,6)
kow [346]

Using the mid-point concept, it is found that point B is located at coordinates (-6.5, 0).

<h3>What is the midpoint concept?</h3>

The midpoint between two points is the halfway point between them, and is found using the mean of the coordinates.

The center is the midpoint of the two coordinates of the diameter, hence:

C = \frac{B + A}{2}

For the x-coordinate:

-3 = \frac{x + 0.5}{2}

x + 0.5 = -6

x = -6.5

For the y-coordinate:

3 = \frac{y + 6}{2}

y + 6 = 6

y = 0

More can be learned about the mid-point concept at brainly.com/question/10956693

#SPJ1

3 0
2 years ago
In a group of Explore students, 38 enjoy video games, 12 enjoy going to the movies and 24 enjoy solving mathematical problems. O
Elodia [21]

Answer:

The number of students that like only two of the activities are 34

Step-by-step explanation:

Number of students that enjoy video games, A = 38

Number of students that enjoy going to the movies, B = 12

Number of students that enjoy solving mathematical problems, C = 24

A∩B∩C = 8

Here we have;

n(A∪B∪C) = n(A) + n(B) + n(C) - n(A∩B) - n(B∩C) -n(A∩C) + n(A∩B∩C)

= 38 + 12 + 24 - n(A∩B) - n(B∩C) -n(A∩C) + 8

Also the number of student that like only one activity is found from the following equation;

n(A) - n(A∩B) - n(A∩C) + n(A∩B∩C) + n(B) - n(A∩B) - n(B∩C) + n(A∩B∩C) + n(C) - n(C∩B) - n(A∩C) + n(A∩B∩C) = 30

n(A) + n(B) + n(C) - 2·n(A∩B) - 2·n(A∩C) - 2·n(B∩C) + 3·n(A∩B∩C) = 30

38 + 12 + 24 - 2·n(A∩B) - 2·n(A∩C) - 2·n(B∩C) + 24 = 30

- 2·n(A∩B) - 2·n(A∩C) - 2·n(B∩C) = -68

n(A∩B) + n(B∩C) + n(A∩C) = 34

Therefore, the number of students that like only two of the activities = 34.

8 0
3 years ago
In column C, there are too many numbers after the decimal place. Karl does not need this level of detail as it is distracting fr
Gemiola [76]

Round his data to 2 decimal places

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The minimum value for the function is -6
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