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vredina [299]
3 years ago
6

Carl is boarding a plane. He has 222 checked bags of equal weight and a backpack that weighs 4 \text{ kg}4 kg4, start text, spac

e, k, g, end text. The total weight of Carl's baggage is 35 \text{ kg}35 kg35, start text, space, k, g, end text.
Mathematics
1 answer:
Finger [1]3 years ago
4 0

Answer:

khanacademy is always watching be aware

Step-by-step explanation:

You might be interested in
@Apologiabiology mind helping once more?
Kisachek [45]
Domain is all real, yep
vertex of y values is from2 to infinity, so 2nd is false
y int is where x=0, that is at y=2, nope so 3rd is false
2 up and 1 to left, so no for 4th
x intercept? there are none


answer is only first option
6 0
3 years ago
Find the general solution for the differential equation \displaystyle{\left.{d}{y}\right.}+{9}{x}\ {\left.{d}{x}\right.}={0}dy+9
densk [106]

Answer:

y= CC-4.5x^2

Step-by-step explanation:

To find the general solution to the differential equation

dy + 9x dx = 0, we employ the method of separating variable as follows:

Note: { will represent the integral sign here.

Separating the variables and integrating, we have

{dy  = -{9x dx

y = -(9/2)(x^2) + CC,

where CC is the given constant of integration.

This can be rearranged/simplified to yield

y= CC-4.5x^2

6 0
3 years ago
3. A rocket is launched vertically from the ground with an initial velocity of 64 ft / sec . ( a ) Write a quadratic function h
lys-0071 [83]

Answer:

See below.

Step-by-step explanation:

The rocket's  flight is controlled by its initial velocity and the acceleration due to gravity.

The equation of motion is h(t) = ut + 1.2 g t^2 where  u = initial velocity, g = acceleration due to gravity ( = - 32 ft s^-2) and t = the time.

(a) h(t) = 64t  - 1/2*32 t^2

h(t) = 64t - 16t^2.

(b) The graph will be a parabola which opens downwards  with a maximum at the point (2, 64) and x-intercepts at (0, 0) and (4, 0).

The y-axis is the height of the rocket and the x-axis  gives the time.

Maximum height = 64 feet, Time to maximum height = 2 seconds, and time in the air = 4 seconds.

6 0
3 years ago
Read 2 more answers
15 times a number increased
Minchanka [31]

Answer:

Step-by-step explanation:

k

6 0
3 years ago
Read 2 more answers
A woman is standing at the edge of a slow-moving river which is one mile wide, and she wishes to return to her campground on the
vesna_86 [32]

Answer:

the best option would be to swim

Step-by-step explanation:

Hello! To solve this problem we must follow the following steps.

1. remember the concept of uniform motion with constant speed, which establishes the following equation

t=\frac{X}{V}

where

t=time

x=distance

V=speed

2. Calculate the time it takes to swim and calculate the time it takes to walk

walking:

x=10mile

v=5milles/h

t=\frac{10}{5} =2h

swimming

x=1mile

v=3milles/h

t=\frac{1}{3} =0.3h

3. Compare both results and choose the one with the least time.

as you can see it takes less time swimming, so this would be the best way

7 0
3 years ago
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