A pharmacist has 40% and 80% of iodine solutions on hand. How many liters of each iodine solution will be required to produce 4 liters of a 50% iodine mixture?
.
Let x = liters of 40% iodine
then
4-x = liters of 80% iodine
Using algebra:
.40x + .80(4-x) = .50(4)
.40x + 3.20-.80x = 2
3.20-.40x = 2
x = 4 liters (40% iodine)
80% iodine:
4-x = 4-4 = 0 liters needed (80% iodine)
In the familiar decimal number system that we use every day, moving the place
of a digit changes its value by a power of 10 .
In a system of numbers to any other base, moving the place of a digit changes
its value by a power of whatever the base of that number system is.
400,000 60,000
0,000
000
50
3
Because 2x2x2x2 = 8 and then you multiply it with 4 which is .. 32 and 6x12 is equal to 6x6x6x6x6x6x6x6x6x6x6x6x6x6x6x6 is equal to 2176782336
I think it’s d I’m not sure though
