Step 1
find the perimeter of a <span>single enclosure
perimeter of a square=4*b
where b is the long side of a square
area square=b</span>²
area square=2025 ft²
b²=2025-------> b=√2025-----> b=45 ft
<span>so
perimeter=4*45-------> 180 ft
step 2
</span>find the perimeter of a two individual enclosure
<span>perimeter=4*20+3*40------> 200 ft
area=20*40*2------> 1600 ft</span>²
<span>
therefore
fencing singular enclosure < fencing two individual enclosure
180 ft < 200 ft
</span>area singular enclosure > area two individual enclosure
2025 ft² > 1600 ft²<span>
the answer is the option
</span><span>a The singular enclosure would minimize cost because it requires 180 feet of fencing.</span><span>
</span>
Given :
A particle moves in the xy plane starting from time = 0 second and position (1m, 2m) with a velocity of v=2i-4tj .
To Find :
A. The vector position of the particle at any time t .
B. The acceleration of the particle at any time t .
Solution :
A )
Position of vector v is given by :
B )
Acceleration a is given by :
Hence , this is the required solution .
Answer:
He paid $9 twelve times
12× 2= 24 days
Step-by-step explanation:
1st day = $16.60
3rd day=$ 9 (i.e for every 2days afterwards)
5th day=$ 9
Yuri pays : 124.60
124.60-16.60
= $108.00
After paying the first day he paid 108.00
108.00÷ 9 = 12
He paid $9 twelve times
12× 2= 24 days
✧･ﾟ: *✧･ﾟ:* *:･ﾟ✧*:･ﾟ✧
Hello!
✧･ﾟ: *✧･ﾟ:* *:･ﾟ✧*:･ﾟ✧
❖ The area is 169 square cm.
Find the value of each side (a square has 4 sides so divide by 4 ):
52/4 = 13
To find the area of a square, you only need 2 sides so multiply 2 sides:
13 x 13 = 139
Area = 139 square cm
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