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3 years ago

What is the solution to the equation below?

Mathematics

1 answer:

Norma-Jean [14]3 years ago

7 0

Answer:

Step-by-step explanation:

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If aſc and a +b = C, prove that a|b.

mars1129 [50]

Answer with Step-by-step explanation:

Since we have given that

a + b = c

and a|c

i.e. a divides c.

We need to prove that a|b.

⇒ a = mb for some integer m

Since a|c,

So, mathematically, it is expressed as

c= ka

Now, we put the above value in a + b = c.

So, it becomes,

$a+b=c\\\\a+b=ka\\\\b=ka-a\\\\b=a(k-1)\\\\\implies a|b$

a=mb, here, m = k-1

Hence, proved.

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3 years ago

Find the length of segment ST A) 74 units B) 12 units C) 10 units D) 74 units

vodomira [7]

74 units would be your answer for the length segment

4 0

3 years ago

Help!! Plz complete these two :)

ella [17]

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2 years ago

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Evaluate the surface integral S F · dS for the given vector field F and the oriented surface S. In other words, find the flux of

Tomtit [17]

Apparently my answer was unclear the first time?

The flux of F across S is given by the surface integral,

$\displaystyle\iint_S\mathbf F\cdot\mathrm d\mathbf S$

Parameterize S by the vector-valued function r(u, v) defined by

$\mathbf r(u,v)=7\cos u\sin v\,\mathbf i+7\sin u\sin v\,\mathbf j+7\cos v\,\mathbf k$

with 0 ≤ u ≤ π/2 and 0 ≤ v ≤ π/2. Then the surface element is

dS = n • dS

where n is the normal vector to the surface. Take it to be

$\mathbf n=\dfrac{\frac{\partial\mathbf r}{\partial v}\times\frac{\partial\mathbf r}{\partial u}}{\left\|\frac{\partial\mathbf r}{\partial v}\times\frac{\partial\mathbf r}{\partial u}\right\|}$

The surface element reduces to

$\mathrm d\mathbf S=\mathbf n\,\mathrm dS=\mathbf n\left\|\dfrac{\partial\mathbf r}{\partial u}\times\dfrac{\partial\mathbf r}{\partial v}\right\|\,\mathrm du\,\mathrm dv$