Answer:
ik bro sorry I didn't get back to you in a little bit and then I'll
Answer:
B) The maximum y-value of f(x) approaches 2
C) g(x) has the largest possible y-value
Step-by-step explanation:
f(x)=-5^x+2
f(x) is an exponential function.
Lim x→∞ f(x) = Lim x→∞ (-5^x+2) = -5^(∞)+2 = -∞+2→ Lim x→∞ f(x) = -∞
Lim x→ -∞ f(x) = Lim x→ -∞ (-5^x+2) = -5^(-∞)+2 = -1/5^∞+2 = -1/∞+2 = 0+2→
Lim x→ -∞ f(x) = 2
Then the maximun y-value of f(x) approaches 2
g(x)=-5x^2+2
g(x) is a quadratic function. The graph is a parabola
g(x)=ax^2+bx+c
a=-5<0, the parabola opens downward and has a maximum value at
x=-b/(2a)
b=0
c=2
x=-0/2(-5)
x=0/10
x=0
The maximum value is at x=0:
g(0)=-5(0)^2+2=-5(0)+2=0+2→g(0)=2
The maximum value of g(x) is 2
The remainder for 67 divided by 3 would be 1 because (this might be a bad explanation since i'm not good at explaining math without showing u my work) if u do divide 6 by 3, 3x2 is 6 and 6-6 is 0. Then if u divide 7 by 3, then 6 is the closest u can get to 7 without multiplying by a decimal. Then if u do 7-6, u get 1 and u cant divide 1 by 3 so the remainder would be 1.
Answer:
36. Limit = 2/3.
Step-by-step explanation:
36.
(∛ x- 1) / (√x - 1)
Rationalise the expression:-
Multiply top and bottom by (√x + 1):-
(∛x - 1)(√x + 1) / (√x - 1)(√x + 1)
= x^5/6 + ∛x - √x - 1 / (x - 1)
Applying L'hopital's rule ( differentiating top and bottom of the fraction) we have:
Limit as x ----> 1 of [5/6 x^-1/6 + 1/3 x^(-2/3) - 1/2x^-1/2] / 1
= 5/6(1) + 1/3(1) - 1/2(1) = 2/3 (answer).
Answer:
for Part A
Answer is C.
Step-by-step explanation:
Here the angle, a is 60°, Opposite is 20 and adjacent is x.
Therefore we have,
Making x the subject gives us
Part B
Value of x to the nearest tenth
