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3 years ago

9

The variables x and y vary directly. Use the values to find the constant of proportionality. Then write an equation that relates

x and y. y=72; x=3

1 answer:

uysha [10]3 years ago

5 0

2y + 4x = 144+ 12= 156

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CAN SOMEONE PLEASE HELP ME WITH THIS QUESTION?

Dimas [21]

Answer:

B. More than one quadrilateral exists with the given conditions, and all instances must be isosceles trapezoids.

Step-by-step explanation:

In a parallelogram, adjacent angles are supplementary. They are only congruent if the parallelogram is a rectangle. In this problem, adjacent angles are both congruent and acute. If this were a triangle, it would guarantee the triangle is isosceles.

The fact that opposite angles are supplementary guarantees that the fourth side of the figure is parallel to the base between the acute angles. That makes the figure an isosceles trapezoid. Unless specific angles and side lengths are specified, the description matches <em>any</em> isosceles trapezoid.

4 0

3 years ago

Determine if the following system of equations has no solutions, infinitely many

DochEvi [55]

Answer:

There is one solution

Step-by-step explanation:

2x + y = -1

8x + 3y = -2

Multiply the first equation by -4

-8x -4y = 4

Then add the equations together to eliminate x

-8x -4y = 4

8x + 3y = -2

--------------------

-y = 2

Multiply by -1

y =-2

Now find x

2x+y =-1

2x+-2 =-1

Add 2 to each side

2x-2+2=-1+2

2x=1

Divide by 2

x = 1/2

8 0

3 years ago

26 = 3x - 2 - 7x show york work but please try to summarize you're explanation

Delvig [45]

26 = 3x - 2 - 7x
26 + 2 = -4x
28 / -4 = x
x = -7
Best answer me please!

6 0

3 years ago

Which equation would help you find the missing side length in the right triangle shown?

irina [24]

Equation a^2 + b^2 = c^2
c = longest side, unknown
The answer is D.
12^2 + 10^2 = c^2

7 0

3 years ago

Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre

Alekssandra [29.7K]

In the given figure we can determine the coordinate of point M from the graph, we get:

$M=(\frac{d}{2},\frac{c}{2})$

We can also determine the coordinates of point N as:

$N=(\frac{a+b}{2},\frac{c}{2})$

Now, to determine the length of segment MN, we need to subtract the x-coordinate of M from the coordinates of N, we get:

$MN=\frac{a+b}{2}-\frac{d}{2}$

Subtracting the fractions we get:

$MN=\frac{a+b-d}{2}$

Now, to obtain the length of AB we need to subtract the x-coordinate of A from the x-coordinate of B.

The coordinates of A are determined from the graph:

$A=(0,0)$

The coordinates of B are:

$B=(a,0)$

Therefore, the length of segment AB is:

$AB=a$

Now we do the same procedure to determine the segment of CD. The coordinates of C are:

$C=(b,c)$

The coordinates of D are:

$D=(d,c)$

Therefore, CD is:

$CD=b-d$

Now, we determine MN as half the sum of the bases. The bases are AB and CD, therefore:

$MN=\frac{1}{2}(a+b-d)$

Therefore, we have proven that the median of a trapezoid equals half the sum of its bases.

8 0

1 year ago