3 similar shirts and 4 similar jackets cost $360. 1 such shirt and 3 such jackets cost $220. Find the costof each shirt.
1 answer:
3s + 4j = 360 1s + 3j = 220 This one we can solve using substitution, in that s + 3j = 220 implies s = 220 - 3j (subtract 3j from each side). Now substitute into the first equation: 3(220 - 3j) + 4j = 360. Solve for jackets. 660 - 9j + 4j = 360 [Distributive property] 660 - 5j = 360 [Add -9j + 4j] Subtract 360 from each side, and add 5j to each side. 660 - 360 - 5j + 5j = 360 - 360 + 5j 300 = 5j Divide each side by 5. $60 = price of a jacket. Three of these plus a shirt runs $220. 3(60) = 180 180 + s = 220 180 - 180 + s = 220 - 180 [Subtract 180 from each side] s = 40 Now we double check. 3(40) + 4 (60) = 120 + 240 = 360. This satisfies the first equation. We could check the second one too, but I'm satisfied.
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Answer:
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Step-by-step explanation:
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