All categories

4 years ago

What is the value of x? Enter your answer in the box.

Mathematics

2 answers:

MAXImum [283]4 years ago

7 0

Sides: a = 3 b = 2 c = 4 those are the answers i found.

Andreyy894 years ago

3 0

3 sides are equal
so
4x - 30 = 3x - 5
4x - 3x = -5 + 30
x = 25

You might be interested in

Slope intersect form

pochemuha

Well... you need to find your slope first for starters. In order to find you slope it would be y2-y1/x2-x1... rise/run. So that would make your slope 6/3 and you can simplify that to 2/1 because divide it by 3. In order to find your y-intercept, you need to have (x) at 0 and wherever (y) is on that line, it would be your y-intercept.

6 0

3 years ago

In, z = 4 cm, x=8cm, and m

Rzqust [24]

Answer:

what do u want us to do pls be more clear!

5 0

3 years ago

Which is the graph of y – 3 =-2/3 (x + 6)?

Tresset [83]

Answer:

see graph below

7 0

3 years ago

If a person takes a prescribed dose of 10 milligrams of Valium, the amount of Valium in that person's bloodstream at any time ca

aleksandr82 [10.1K]

Answer:

(a)8.0mg

(b)36.87 hours

(c)-0.168

Step-by-step explanation:

The amount of Valium in that person's bloodstream at any time can be modeled with the exponential decay function $A ( t ) = 10 e^{ -0.0188 t$ (t in hours)

(a)After 12 Hours

$A ( 12) = 10 e^{ -0.0188*12}\\=7.98\\\approx 8.0 mg $(to the nearest tenth of a milligram)$

(b)If A(t)=5mg

Then:

$5= 10 e^{ -0.0188 t}\\$Divide both sides by 10\\0.5=e^{ -0.0188 t}\\$Take the natural logarithm of both sides\\ln (0.5)=-0.0188 t\\t=ln (0.5) \div (-0.0188)\\$t=36.87 hours (to two decimal places.)$

(c)

$A ( t ) = 10 e^{ -0.0188 t}\\A'(t)=10(-0.0188)e^{ -0.0188 t}\\A'(t)=-0.188e^{ -0.0188 t}\\$At 6 hours, the rate at which the amount of Valium is decaying therefore is:\\A'(6)=-0.188e^{ -0.0188*6}\\$=-0.168 ( to three decimal places)$

3 0

3 years ago

A total of 706 tickets were sold for the school play. They were either adult tickets or student tickets. There were 56 more stud

sleet_krkn [62]

325 adult tickets were sold

Solution:

Let "a" be the number of adult tickets sold

Let "s" be the number of student tickets sold

Given that total 706 tickets were sold for the school play

Therefore,

number of adult tickets sold + number of student tickets sold = 706

a + s = 706 --------- eqn 1

There were 56 more student tickets sold than adult tickets

Number of student tickets sold = 56 + number of adult tickets sold

s = 56 + a ------- eqn 2

Let us solve eqn 1 and eqn 2

Substitute eqn 2 in eqn 1

a + 56 + a = 706

2a + 56 = 706

2a = 706 - 56

2a = 650

a = 325

Thus 325 adult tickets were sold

6 0

4 years ago