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evablogger [386]

3 years ago

6

Slope intersect form

1 answer:

pochemuha3 years ago

6 0

Well... you need to find your slope first for starters. In order to find you slope it would be y2-y1/x2-x1... rise/run. So that would make your slope 6/3 and you can simplify that to 2/1 because divide it by 3. In order to find your y-intercept, you need to have (x) at 0 and wherever (y) is on that line, it would be your y-intercept.

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What is the slope of this line of best fit?

Bas_tet [7]

Answer:

The slope of the line of best fit is $\frac{-6}{7}$ ⇒ 2nd option

Step-by-step explanation:

The formula of the slope of a line is $m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

<em>To find the slope of the best line fit choose two points their positions make the number of the points over the line equal to the number of the points below the line</em>

From the attached graph points (1 , 9) and (8 , 3) are the best choice

∵ The line passes through points (1 , 9) and (8 , 3)

∴ $x_{1}$ = 1 and $x_{2}$ = 8

∴ $y_{1}$ = 9 and $y_{2}$ = 3

- Substitute them in the formula of the slope

∴ $m=\frac{3-9}{8-1}=\frac{-6}{7}$

∴ The slope of the line of best fit is $\frac{-6}{7}$

6 0

3 years ago

An equation parallel and perpendicular to 4x+5y=19

UNO [17]

Answer:

Parallel line:

$y=-\frac{4}{5}x+\frac{9}{5}$

Perpendicular line:

$y=\frac{5}{4}x-\frac{1}{2}$

Step-by-step explanation:

we are given equation 4x+5y=19

Firstly, we will solve for y

$4x+5y=19$

we can change it into y=mx+b form

$5y=-4x+19$

$y=-\frac{4}{5}x+\frac{19}{5}$

so,

$m=-\frac{4}{5}$

Parallel line:

we know that slope of two parallel lines are always same

so,

$m'=-\frac{4}{5}$

Let's assume parallel line passes through (1,1)

now, we can find equation of line

$y-y_1=m'(x-x_1)$

we can plug values

$y-1=-\frac{4}{5}(x-1)$

now, we can solve for y

$y=-\frac{4}{5}x+\frac{9}{5}$

Perpendicular line:

we know that slope of perpendicular line is -1/m

so, we get slope as

$m'=\frac{5}{4}$

Let's assume perpendicular line passes through (2,2)

now, we can find equation of line

$y-y_1=m'(x-x_1)$

we can plug values

$y-2=\frac{5}{4}(x-2)$

now, we can solve for y

$y=\frac{5}{4}x-\frac{1}{2}$

4 0

3 years ago

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Answer:

use distributive and combine like terms

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