Answer:
175°
Step-by-step explanation:
Bearing angles are usually measured clockwise from North. Reverse bearing angles differ from forward bearing angles by 180°. These relations and the usual angle sum relation for a triangle can be used to solve this problem.
Angle PQR will be the difference in the bearings from Q to P and Q to R:
∠PQR = 124° -46° = 78°
Triangle PQR is isosceles, so the base angle at P will be ...
∠QPR = (180° -78°)/2 = 51°
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The bearing from P to R will be 51° less than the bearing from P to Q. The bearing from P to Q is 180° more than the bearing from Q to P.
PR bearing = PQ bearing - ∠QPR
= PQ bearing - 51°
= (46° +180°) -51° = 175°
The bearing of R from P is 175°.
It would be x<span>≤5. She can get the maximum of 5 shirts, or less. </span>
<em>Product hints at multiplication so -5n is AT LEAST meaning that it is at or greater than 35....</em>
<em />
-5n ≥ 35
Answer: ![2.09ft^3](https://tex.z-dn.net/?f=2.09ft%5E3)
Step-by-step explanation:
![Formula: V=\pi r^2 \frac{h}{3}](https://tex.z-dn.net/?f=Formula%3A%20V%3D%5Cpi%20r%5E2%20%5Cfrac%7Bh%7D%7B3%7D)
Plug in your values.
![V=(3.14)(1ft)^2(\frac{2ft}{3})](https://tex.z-dn.net/?f=V%3D%283.14%29%281ft%29%5E2%28%5Cfrac%7B2ft%7D%7B3%7D%29)
Square 1ft.
![V=(3.14)(1ft^2)(\frac{2ft}{3})](https://tex.z-dn.net/?f=V%3D%283.14%29%281ft%5E2%29%28%5Cfrac%7B2ft%7D%7B3%7D%29)
Plug this into a calculator or do it manually.
![V=2.09ft^3](https://tex.z-dn.net/?f=V%3D2.09ft%5E3)