Answer:
51,111%
Step-by-step explanation:
We know that 45% have a dog but no cat. While 23% have both a dog and a cat.
Then Pr(X has cat|X has dog) = Pr(X has dog and cat)/Pr(X has dog)
= Pr(X has dog and cat)/Pr(X has dog) = 0.23/0.45 = 0.51 ≈ 51,111%
The probability that a student’s family owns a cat if the family owns a dog is 51,111%
Answer:
1.) n-10
2.) 4 / x=x (dont trust me on this)
3.) -8n+1
4.) 1/2 - 19 ( dont trust me on this)
5.)3/5-21 or 3/5>21
6.)x^+15
Step-by-step explanation:
I tried double check it
its been awhile
Answer:
so i think this may be right
A small Bucket can hold 75% more then a large Cup
If the bucket holds 36 units
36x.25=9
the large cup holds 9 units
Step-by-step explanation:
Answer:
-1, 3, 7, 11
Step-by-step explanation:
First, let's find term 1. To find this term, we need to replace n with 1 - what is 4(1) - 5? Well, that's just 4 - 5, or -1. So, our first term is -1. Next, we'll find our second term. To do this, we'll replace n with 2. 4(2) = 8, and then 8 - 5 is equal to 3, so our second term is 3. Let's now find the third term by replacing n with the number 3. 4(3) - 5 is equal to 12 - 5, or 7. So, 7 is our third term. Finally, we'll find the fourth term. 4(4) is equal to 16, and 16 - 5 is equal to 11. So, the fourth and final term is equal to 11.
Hopefully that's helpful! :)
