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ehidna [41]
3 years ago
7

What is the height and length of a rectangular box with a volume of 6x^2-600 with a width of 6

Mathematics
1 answer:
harina [27]3 years ago
7 0

Answer:

(x+10) and (x-10)

Step-by-step explanation:

The volume of a rectangular box is defined as

Volume = width*height*length

In this case

Volume  = 6x^2-600  =  6*(x^2 - 100)

And we also know,

Volume  =  (6)*height*length

So,

6*(x^2 - 100) = (6)*height*length

This means that

height*length = (x^2 - 100)

height*length = (x+10)*(x-10)

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Mr. and Mrs. Chan want to buy new furniture that has a cash price of $6230. On the installment plan, they must pay %25 of the ca
Masteriza [31]

The interest due on financing option is $307.50

What is interest on financing?

Interest on financing is the extra amount paid by the couple when their total payments are compared to the cash price of $6,230.

The total payments would be the 25% down payment plus the sum of the twelve monthly payments of $415 each

Down payment=cash price*25%

Down payment=$6230*25%

Down payment=$1,557.50

Total monthly payments=amount of each monthly payment*number of monthly payments

monthly payment=$415

number of monthly payments=12

Total monthly payments=$415*12

Total monthly payments=$4,980

Total payment under financing=Down payment +Total monthly payments

Total payment under financing=$1,557.50+$4,980

Total payment under financing=$6,537.50

Interest=$6,537.50-$6,230

Interest on financing=$307.50

Find out more on down payment on: brainly.com/question/1698287.

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Complete question:

Mr. and Mrs. Chan want to buy new furniture that has a cash price of $6230. On the installment plan, they must pay %25 of the cash price as a down payment and make twelve monthly payments of $415. How much interest did they pay due to financing?

3 0
2 years ago
Please answer asap please
viva [34]
70+70= 140 points gained minus 145 points lost or 140 - 145= -5 points.
3 0
3 years ago
. a thin plate made of iron is located in the xy-plane. the temperature t in degrees celsius at a point p(x,y) is inversely prop
harkovskaia [24]

The level of the curves are all the eclipses with the major axis.

             100                        50          1

a2 =       ------  - 1   ,   b2 =   -------  -   -----

               C                            C           2

Given that:

               100

T(x, y) = ------------

               1 + x2 + y2

This implies that the level curves of a function(f) of two variables relate to the curves with equation f(x, y) = c

where c is the constant.

                 100

        C = ------------                          ----- (1)

             1 + x2 + y2

By cross multiply

C (1 + x2 + y2) = 100

1 + x2 + y2 = 100/C

       

               100

x2 + y2= ---------  - 1                    -----(2)

                 C

From (2); let's assume that the values of c > 0 likewise c < 100, then the interval can be expressed as 0 < c <100.

Now,

(x)2           (y)2

------   +     ---------------

100            50          1

------  - 1     -------  -   -----

C                C           2

This is the equation for the  family of the eclipses centered at (0,0) is :

x2/a2 + y2/b2 = 1

             100                        50          1

a2 =       ------  - 1      b2 =   -------  -   -----

              C                            C           2

Therefore; the level of the curves are all the eclipses with the major axis:

             100                        50          1

a2 =       ------  - 1      b2 =   -------  -   -----

              C                            C           2

 and a minor axis   which satisfies the values for which 0< c < 100.

The sketch of the level curves can be see in the attached image below.

To learn more about Plane of Axis visit:

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6 0
1 year ago
Arthur is conducting a study on the preferred study options of students from East County College. He randomly selected 32 studen
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Answer:

D. As the sample size is appropriately large, the margin of error is ±0.15

Step-by-step explanation:

The number of students in the sample, n = 32 students

The percentage of the students that preferred studying abroad, \hat p = 25%

The confidence level for the study = 95%

As a general rule, a sample size of 30 and above are taken as sufficient

The z-value at 95% confidence level, z = 1.96

The margin of error of a proportion formula is given as follows;

M.O.E. =  z^*\times \sqrt{\dfrac{\hat{p} \cdot(1-\hat{p})}{n}}

Therefore, we get;

M.O.E = 1.96\times \sqrt{\dfrac{0.25\times(1-0.25)}{32}} \approx \pm0.15

Therefore, the correct option is that as the sample size is appropriately large, the margin of error is ±0.15.

7 0
3 years ago
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