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2 years ago

Solve for m: m – 4.2 = 5.1

Mathematics

1 answer:

Fantom [35]2 years ago

4 0

Answer:

M equals 9.3

Step-by-step explanation:

To get m alone add 4.2 to each side

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Help me please explain do not need work just explain THANK YOU I NEED HELP

Mnenie [13.5K]

Alright,

you will need to solve for each variable to find if they got the equation correctly or not..

Let's start with h
isolate h
(1/2)h = A/(b1+b2)
Now we need to get rid of 1/2 we may do so by multiplying both sides by 2

h = 2(A/(b1+b2))

And that's not how they did it for h so Option D doesn't apply

Let's see C
Also doesn't apply since they multiplied 2 only by A rather than A/h

Let's see B
Also not correct they made the same mistake as with option C

Let's see A
again same mistake
when multiplying both sides by 2
the 2 should be as following
$2\frac{A}{h}$

I believe you should contact your instructor and explain that non of the options is right.

6 0

3 years ago

Find the equation of a line parallel to – 2y = –2 – 2x that passes through the<br> point (9,-9).

riadik2000 [5.3K]

Answer:

2y + 2x = 0

Step-by-step explanation:

First you have to find the slope of the line.

Parallel lines have same slope

2y = -2-2x

y=-1-1x, y=-1x-1

slope = -1

Use point slope formula

y-y=m(x-x)

y-(-9) = -1(x-9)

y+9 = -1(x-9)

y+9 = -1x+9

y = -x

y + x = 0

2y + 2x = 0

7 0

3 years ago

30 points!!<br> What is the sum of the first six terms of the series?<br> 48 - 12 + 3 - 0.75 +...

Lunna [17]

Answer:

The sum of the first six terms is 38.39

Step-by-step explanation:

This is a geometric sequence since the common difference between each term is $-\frac{1}{4}$

Thus, $r=-\frac{1}{4}$

To find the sum of first six terms, we need to find the fifth and sixth term of the sequence.

To find the fifth term:

The general form of geometric sequence is $a_{n}=a_{1} \cdot r^{n-1}$

To find the fifth term, substitute $n=5$ in $a_{n}=a_{1} \cdot r^{n-1}$

$\begin{aligned}a_{5} &=(48) \cdot\left(-\frac{1}{4}\right)^{5-1} \\&=(48) \cdot\left(-\frac{1}{4}\right)^{4} \\&=(48)\left(\frac{1}{256}\right) \\a_{5} &=0.1875\end{aligned}$

To find the sixth term, substitute $n=6$ in $a_{n}=a_{1} \cdot r^{n-1}$

$\begin{aligned}a_{6} &=(48) \cdot\left(-\frac{1}{4}\right)^{6-1} \\&=(48) \cdot\left(-\frac{1}{4}\right)^{5} \\&=(48)\left(-\frac{1}{1024}\right) \\a_{5} &=-0.046875\end{aligned}$

To find the sum of the first six terms:

The general formula to find Sn for $|r|$ is $S_{n}=\frac{a\left(1-r^{n}\right)}{1-r}$

$\begin{aligned}S_{6} &=\frac{48\left(1-\left(-\frac{1}{4}\right)^{6}\right)}{1-\left(-\frac{1}{4}\right)} \\&=\frac{48\left(1-\frac{1}{4096}\right)}{1+\frac{1}{4096}} \\&=\frac{48(0.95)}{5} \\&=\frac{48(0.9998)}{5} \\&=\frac{48(0.9998)}{5} \\&=\frac{47.9904}{5} \\&=38.39\end{aligned}$