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kipiarov [429]
2 years ago
6

During Raul’s exercise program, he recorded how much weight he lost or gained each week. After 5 weeks, Raul had collected the d

ata shown in the chart. He thought, “I can use the Inverse Property and the Identity Property to help me find out how much my weight has changed.”
week
1 -3
2 -2 1/2
3 +3
4 -1 1/2
5 +1
Why is Raul’s reasoning incorrect?

A. The total of Raul’s numbers is not 0.

B. Raul’s list of numbers does not include 0.

C. Raul’s list of numbers includes opposites.

D. Raul cannot add any of the numbers in his list to get 0.
Mathematics
1 answer:
skelet666 [1.2K]2 years ago
7 0

Answer: A.)The total of numbers is not 0

Step-by-step explanation:

if you look at the data you'll see that there is only one pair that you can use the inverse property equation on but they rest aren't exact opposites.

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solong [7]
5^{2} =25 \\  3^{3} =27 \\  2^{3} =8 \\  4^{3} =64 \\  \\ 27.8=216 \\ 216+25=241 \\  \\  \frac{241}{64} =3,76 \\  \\\framebox[1.1\width]{Good Luck!} \par
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3 years ago
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Connor jogs at a constant rate of 3.5 miles per hour. The table shows the distance traveled for different numbers of hours. Drag
allsm [11]

Answer:

1st and 3rd go in the 1st box

2nd and 4th go in the 2nd box

last one goes in the last box

Step-by-step explanation:

1,2,3,4,5 and time spent jogging go in independent quantity

3.5, 7, 10.5, 14, 17.5 and distance traveled go in dependent quantity

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3 years ago
Erica solved the equation −5x − 25 = 78; her work is shown below. Identify the error and where it was made.
Romashka-Z-Leto [24]
In step one, you are supposed to add 25 to both sides, because if you just subtract, it would be -5x-50=53
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3 years ago
Interpreting composite functions in the real world The volume of air in a balloon is represented by the function v(r)=4/3 ³, whe
adoni [48]

There are two <em>true</em> statements:

  1. When the function is composed with r, the <em>composite</em> function is V(t) = (1/48) · π · t⁶.
  2. V(r(6)) shows that the volume is 972π cubic inches after 6 seconds.

<h3>How to use composition between two function</h3>

Let be <em>f</em> and <em>g</em> two functions, there is a composition of <em>f</em> with respect to <em>g</em> when the domain of <em>f</em> is equal to the range of <em>g</em>. In this question, the <em>domain</em> variable of the function V(r) is replaced by substitution.

If we know that V(r) = (4/3) · π · r³ and r(t) = (1/4) · t², then the composite function is:

V(t) = (4/3) · π · [(1/4) · t²]³

V(t) = (4/3) · π · (1/64) · t⁶

V(t) = (1/48) · π · t⁶

There are two <em>true</em> statements:

  1. When the function is composed with r, the <em>composite</em> function is V(t) = (1/48) · π · t⁶.
  2. V(r(6)) shows that the volume is 972π cubic inches after 6 seconds.

To learn on composition between functions: brainly.com/question/12007574

#SPJ1

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Maybe something money-wise.

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