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likoan [24]
3 years ago
5

Find the mean of the data summarized in the given frequency distribution. Compare the computed mean to the actual mean of 47.3 m

iles per hour.
Mathematics
1 answer:
Marta_Voda [28]3 years ago
6 0

Answer:

\bar X = \frac{2276}{48}=47.417

If we compare this value with the 47.3 proposed we have the following error

Error = \frac{|Actual-real|}{real}*100 = \frac{|47.417-47.3|}{47.3}*100 =0.247\%

The computed mean is close to the actual mean because the difference between the means is less than 5%.  

Step-by-step explanation:

Assuming the following dataset:

Speed   42-45  46-49  50-53  54-57  58-61

Freq.         21        15        6           4          2

And we are interested in find the mean, since we have grouped data the formula for the mean is given by:

\bar X = \frac{\sum_{i=1}^n x_i f_i}{\sum_{i=1}^n f_i}

And is useful construct a table like this one:

Speed     Freq    Midpoint   Freq*Midpoint

42-45       21            43.5       913.5

46-49       15            47.5        712.5

50-53       6             51.5         309

54-57        4            55.5         222

58-61        2             59.5        119

Total       48                           2276

And the mean is given by:

\bar X = \frac{2276}{48}=47.417

If we compare this value with the 47.3 proposed we have the following error

Error = \frac{|Actual-real|}{real}*100 = \frac{|47.417-47.3|}{47.3}*100 =0.247\%

The computed mean is close to the actual mean because the difference between the means is less than 5%.  

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A positive integer is twice another.the sum of the reciprocal of the two positive integer is 3/14. Find the integers
icang [17]

Answer:

\huge\boxed{14\ \text{and}\ 7}

Step-by-step explanation:

n,\ m-\text{positive integer}\\\\n=2m-\text{a positive integer is twice another}\\\\\dfrac{1}{n}+\dfrac{1}{m}=\dfrac{3}{14}-\text{the sum of the reciprocal of the two positive integer is }\ \dfrac{3}{14}\\\\\text{We have the system of equations:}\\\\\left\{\begin{array}{ccc}n=2m&(1)\\\dfrac{1}{n}+\dfrac{1}{m}=\dfrac{3}{14}&(2)\end{array}\right

\text{Substitute (1) to (2):}\\\\\dfrac{1}{2m}+\dfrac{1}{m}=\dfrac{3}{14}\\\\\dfrac{1}{2m}+\dfrac{1\cdot2}{m\cdot2}=\dfrac{3}{14}\\\\\dfrac{1}{2m}+\dfrac{2}{2m}=\dfrac{3}{14}\\\\\dfrac{1+2}{2m}=\dfrac{3}{14}\\\\\dfrac{3}{2m}=\dfrac{3}{14}\Rightarrow2m=14\qquad\text{divide both sides by 2}\\\\\dfrac{2m}{2}=\dfrac{14}{2}\\\\\boxed{m=7}

\text{Substitute it to (1):}\\\\n=2\cdot7\\\\\boxed{n=14}

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2 years ago
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━━━━━━━━━━━━━━━ ♡ ━━━━━━━━━━━━━━━  

Since Solise want to plant both trees and bushes in the same number of rows, you need to find the common factor.

Since the question is asking what the greatest number of rows she can plant, you have to find the greatest common factor.

The greatest common factor of 24 and 16 is 8.

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So the greatest number of rows Solise can plant is 8 rows.

━━━━━━━━━━━━━━━ ♡ ━━━━━━━━━━━━━━━  

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