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mr Goodwill [35]
3 years ago
14

What is 8,236 rounded by tenths?

Mathematics
2 answers:
rusak2 [61]3 years ago
8 0

I believe the answer is 8.2

Elanso [62]3 years ago
4 0

Answer:8240

Step-by-step explanation:

Remember, we did not necessarily round up or down, but to the ten that is nearest to 8236.

First, 8236 rounded to the nearest ten is:

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Let g represent Mia’s score. Which expression represents 57 more than 3 times Mia’s score?
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Find out the answers to this
meriva

Answer:

\tan \theta = - \frac{1}{5} = - 0.2

\cos \theta = 0.98

\sin \theta = - 0.196

Step-by-step explanation:

It is given that \cot \theta = - 5 and \theta is in the fourth quadrant.

So, only \cos \theta will have positive value and \sin \theta, \tan \theta will have negative value.

Now, \cot \theta = - 5

⇒ \tan \theta = \frac{1}{\cot \theta} = -\frac{1}{5} (Answer)

We know, that \sec^{2} \theta - \tan^{2} \theta = 1

⇒ \sec \theta = \sqrt{1 + \tan^{2} \theta } = \sqrt{1 + (- \frac{1}{5} )^{2} } = 1.019

{Since, \cos \theta is positive then \sec \theta will also be positive}

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We know, that \csc^{2} \theta - \cot^{2} \theta = 1

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{Since, \sin \theta is negative then \csc \theta will also be negative}

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4 0
3 years ago
The smallest square number which can be divisible by 11 and 5​
Elena L [17]

Answer:

3025

Step-by-step explanation:

let's look at it in this concept.

For a number to be divisible by 11 and 5. it must be a multiple of the LCM of 11 and 5.

LCM of 11 and 5=55

therefore the number is 55x, where x is a positive integer.

it is a said that the number is a perfect square

therefore the square root of 55x must be an integer.

\sqrt{55x}  =  \sqrt{5 \times 11 \times x}

the smallest value of x to make 55x a perfect square is....

x = 11 \times 5 = 55

Therefore the number is.... .

55x = 55(55) = 3025

<em>sweet</em><em> </em><em>right</em>

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