The maximum weight that could be held would be 32 pounds. or six five pound weights taking up 18 inches of space, and weighing 30 Lbs, and two one pound weights adding another two inches. You could achieve a greater weight if you had a weight of one-half inch, in which case you could take six 5 lb weights and 1 two pound weight, then you could add a half inch weight bringing the weight to over 32 inches. Since we don't have a half inch weight we can't raise the weight above 32lbs.
You need to subtract 25 by 18
I think it is .8 i could be wrong i’m not sure
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Answer:</h2>
This is impossible to solve.
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Step-by-step explanation:</h2>
For an equation or inequality to be solvable, there must be the same number of inequalities as variables. Here, there is an x and there is a y. This means that you need at least two inequalities to solve it.
You can, however, rearrange to get x or y on one side.
This can be done for x:
5x < 10 + 2y
x < 2 + 2/5y
Or it can be done for y:
5x < 10 + 2y
5x - 10 < 2y
2.5x - 5 < y
Answer: 1+1 = 2 :)
Step-by-step explanation:
