3 years ago

What is the inverse function of g(x)=1/x-2

1 answer:

3 0

Assuming it's $g(x)=\dfrac{1}{x-2}$

$y=\dfrac{1}{x-2}\\ x-2=\dfrac{1}{y}\\ x=\dfrac{1}{y}+2\\ g^{-1}(x)=\dfrac{1}{x}+2$

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