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zaharov [31]
3 years ago
5

What is the inverse function of g(x)=1/x-2

Mathematics
1 answer:
kkurt [141]3 years ago
3 0
Assuming it's g(x)=\dfrac{1}{x-2}

y=\dfrac{1}{x-2}\\ x-2=\dfrac{1}{y}\\ x=\dfrac{1}{y}+2\\ g^{-1}(x)=\dfrac{1}{x}+2
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What is an equation of the line that passes through the point (-6, -7) and is
Alexandra [31]

Answer:

Step-by-step explanation:

Product of slope of perpendicular lines = -1

6x + 5y = 30

Write this equation in y = mx + b  form

        5y = -6x + 30

          y = \frac{-6}{5}x+\frac{30}{5}

          y=\frac{-6}{5}x + 6

Slope of this line m₁ = -6/5

m₁ * m₂ = -1

      m₂ = -1÷m₁ = -1 * \frac{5}{-6}  

m_{2}=\frac{5}{6}     & (-6 , -7)

Equation of the required line: y - y₁ = m (x - x₁)

y - (-7) = \frac{5}{6}(x - [-6])\\\\y + 7 = \frac{5}{6}x + 6 *\frac{5}{6}\\\\y = \frac{5}{6}x +5-7\\\\y=\frac{5}{6}x-2

8 0
2 years ago
A movie rental company charges a yearly membership fee of $18.Each movie rental is $1.50.Which equation could be used to find th
Pavlova-9 [17]

Answer:

18+1.50m

Step-by-step explanation:

7 0
3 years ago
Mr. Jones eats out at his favorite buffet restaurant every Friday night. If the cost is $9 and he budgets $42 for the month, how
alexandr402 [8]

Answer:

He will be able to eat nine times.

Step-by-step explanation:

Because nine times nine is 91 which is on one less then what he has, so that means he will be able to eat there nine times. Hope I helped

7 0
2 years ago
PLEASE HELP QUICK ITS ALMOST DUE!
konstantin123 [22]
if you start at the point (0,1), you are going to go up and over to (-2,4), which means you will go up 3 and to the left, which means negative, 2
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4 0
3 years ago
The first term of an AP is -7 and the ratio of the eight term to the third term is 7:1 calculate the common difference
alukav5142 [94]

Answer:

the common difference is 6.

Step-by-step explanation:

Given;

first term of an AP, a = -7

let the common difference = d

The third term is written as;

T₃ = a + 2d

The eight term is written as;

T₈ = a + 7d

The ratio of the eight term to third term = 7:1

\frac{T_8}{T_3} = \frac{7}{1} = \frac{a+ 7d}{a + 2d} \\\\7 =  \frac{a+ 7d}{a + 2d}\\\\Recall, a = -7\\\\7 =   \frac{-7+ 7d}{-7 + 2d}\\\\7(-7 + 2d) = -7+ 7d\\\\-49 + 14d = -7 + 7d\\\\14d -7d = -7 + 49\\\\7d = 42\\\\d = \frac{42}{7} \\\\d = 6

Therefore, the common difference is 6.

4 0
2 years ago
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