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zaharov [31]
3 years ago
5

What is the inverse function of g(x)=1/x-2

Mathematics
1 answer:
kkurt [141]3 years ago
3 0
Assuming it's g(x)=\dfrac{1}{x-2}

y=\dfrac{1}{x-2}\\ x-2=\dfrac{1}{y}\\ x=\dfrac{1}{y}+2\\ g^{-1}(x)=\dfrac{1}{x}+2
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