Question

What is the inverse function of g(x)=1/x-2

Answer 1

Assuming it's $g(x)=\dfrac{1}{x-2}$

$y=\dfrac{1}{x-2}\\ x-2=\dfrac{1}{y}\\ x=\dfrac{1}{y}+2\\ g^{-1}(x)=\dfrac{1}{x}+2$