I've forgotten how to work out these kind of problems...could someone explain please? Will give brainiest. (Picture attached)
2 answers:
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Answer:
As x→∞, f(x)→∞
and as x→-∞, f(x)→-∞
Step-by-step explanation:
View Image.
Your first step is to look at the highest value exponent.
In this case it's x⁵.
If the highest exponent is an odd number, the graph will look like a sideway S as shown in the picture below. You can see as you move farther to the right, the y value approaches positive infinity hence "As x→∞, f(x)→∞".
As you move farther left, the graph reaches negative infinity, hence "as x→-∞, f(x)→-∞".
Anyway, if your exponent were to be an even number then you're graph would look like a parabola (looks like a letter U) and f(x) would reach positive infinity when moving to the right side and left side.
Answer:
The area of the shape is
Step-by-step explanation:
we know that
The area of the shape is the area of a three quarter of circle
The area of a three quarter of circle is equal to
we have
substitute
Answer:
A) See the picture
B) 14
C) 45%
Step-by-step explanation:
A) To create a histogram like the one on the picture you can use an online tool like socscistatistics where the number of classes is customizable
B) Because the question B and C have to be responded using a frequency table with 8 classes the answer is 14; the method of using cumulative frequency tables should only be considered as a way of estimation, that is because you obtain values that depend on your choice of class intervals. The way to get a better answer would be to use all the scores in the distribution
Pc1 = 100*(4/40) = 10
Pc2 = 100*(4/40) = 10
Pc3 = 100*(3/40) = 7.5
Pc4 = 100*(11/40) = 27.5
Pc5 = 100*(5/40) = 12.5
Pc6 = 100*(4/40) = 10
Pc7 = 100*(7/40) = 17.5
Pc8 = 100*(2/40) = 5
Pc8 + Pc7 + Pc6 + Pc5 + Pc4 + Pc3 + Pc2 = 90%
Therefore, From class 8 to class 2 is the top 90% of the applicants and the minimum score is 14.
C) Scores equal to or greater than 20 are from class 8 to class 5
Pc8 + Pc7 + Pc6 + Pc5 = 45%
