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A golfer hits an errant tee shot that lands in the rough. A marker in the center of the fairway is 150 yards from the center of

Gwar [14]

$\bold{\huge{\underline{ Solution}}}$

<h3>Given :-</h3>

A marker in the center of the fairway is 150 yards away from the centre of the green
While standing on the marker and facing the green, the golfer turns 100° towards his ball
Then he peces off 30 yards to his ball

We have to find the distance between the golf ball and the center of the green .

<h3>Let's Begin :-</h3>

Let assume that the distance between the golf ball and central of green is x

Here, 

Distance between marker and centre of green is 150 yards
That is, Height = 150 yards
For facing the green , The golfer turns 100° towards his ball
That is, Angle = 100°
The golfer peces off 30 yards to his ball
That is, Base = 30 yards

According to the law of cosine :-

$\bold{\red{ a^{2} = b^{2} + c^{2} - 2ABcos}}{\bold{\red{\theta}}}$

Here, a = perpendicular height
b = base
c = hypotenuse
cos theta = Angle of cosine

So, For Hypotenuse law of cosine will be :-

$\sf{ c^{2} = a^{2} + b^{2} - 2ABcos}{\sf{\theta}}$

Subsitute the required values,

$\sf{ x^{2} = (150)^{2} + (30)^{2} - 2(150)(30)cos}{\sf{100°}}$

$\sf{ x^{2} = 22500 + 900 - 900cos}{\sf{\times{\dfrac{5π}{9}}}}$

$\sf{ x^{2} = 22500 + 900 - 900( - 0.174)}$

$\sf{ x^{2} = 22500 + 900 + 156.6}$

$\sf{ x^{2} = 23556.6}$

$\bold{ x = 153.48\: yards }$

Hence, The distance between the ball and the center of green is 153.48 or 153.5 yards

5 0

2 years ago

Graph of f(x) = 100(0.7)x

Lana71 [14]

Answer:

pay attention in class :)

Step-by-step explanation:

7 0

3 years ago

Write an equation of a line parallel to y=10x+6 and going through point (2,-4)

nadya68 [22]

Answer:

Y= 10x-24 would be parralel to y=10x+6

Step-by-step explanation:

well a parralel line has to have the same slope and a different y-intercept.

To find the y-intercept the x has to be exactly 0.

So we have (2,-4)

The slope is 10/1 which is 10y and 1 x which in an ordered park would be Add 1 x and add 10 y. But we’re trying to get x to be 0 to find the y-intercept.

So subtract 1 x and subtract 10y

2-1=1

-4-10=-14

(1, -14)

1-1=0

-14-10=-24

(0, -24)

THe y-intercept is -24 and w have the slope since its the same thing So

y=10x-24 is the equation

7 0

3 years ago

Please help need someone’s help ASAP

xxTIMURxx [149]

your answer is D

hope this helps

5 0

2 years ago

Read 2 more answers

A company that manufactures storage bins for grains made a drawing of a silo. The silo has a conical base, as shown below: The f

Romashka-Z-Leto [24]

The following that could be used to calculate the total volume of grains that can be stored in the silo is π(2 ft)²8 ft + 1/3π(2 ft)²(9.5 ft - 8ft)

To answer the question, we need to know what volume is.

<h3>What is volume?</h3>

This is the capacity of a material or container.

Since the silo is made of a cylindrical and a conical part, we need to find the volume of both parts.

<h3>Volume of cylindrical part.</h3>

So, the volume of the cylindrical part V = πr²h where

r = radius of cylidrical part = 4 ft/2 = 2 ft and
h = length of cylindrical part = 8 ft.

So, V = πr²h

V = π(2 ft)²8 ft

<h3>Volume of the conical part</h3>

The volume of the conical part is given by V' = 1/3πr²h where

r = radius of cone = 2ft and
h = height of cone.

Since the entire length of silo is 9.5 ft and length of cylindrical part is 8 ft, then the height of cone is h' = 9.5 ft - 8 ft

So, V' = 1/3πr²h'

V' = 1/3π(2 ft)²(9.5 ft - 8ft)

<h3>Total volume of grains in silo</h3>

The total volume of grains equals the total volume of the silo V" = V + V'

V" = π(2 ft)²8 ft + 1/3π(2 ft)²(9.5 ft - 8ft)

So, the following that could be used to calculate the total volume of grains that can be stored in the silo is π(2 ft)²8 ft + 1/3π(2 ft)²(9.5 ft - 8ft)

Learn more about volume here:

brainly.com/question/25248189

#SPJ1

7 0

1 year ago