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2 years ago

The sales tax rate is 4.625%. If Shelley buys a snowboard

1 answer:

8 0

Take 621.52 and multiply by the sales tax rate of 4.625% which you get is 28.7453
Then add price of snowboard to sales tax amount of 28.7453
Total is 650.2653
Round it nearest cent

650.27

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Chick-fil-a has a special going on where you get 2 packs of chicken nuggets for $6.00 and each additional pack is $2.50.

Assoli18 [71]

Answer:

a) (2×6) × (2.5)

b) $16.00

5 0

3 years ago

Find the most general antiderivative of the function. (Check your answer by differentiation. Use C for the constant of the antid

vredina [299]

Answer:

$6t + \frac{t^2}{2}+2/5t^{5/2} + C$

Step-by-step explanation:

Given the expression;

g(t) = 6 + t + t²/√t

This can be rewritten as;

g(t) = 6 + t +t²/t^1/2

g(t) = 6 + t +t^{2-1/2}

g(t) = 6 + t +t^3/2

Integrate the result

$\int\limits {(6 + t+t^{3/2}}) \, dt\\$

Using the formula x^{n+1}/n+1

$\int\limits {(6 + t+t^{3/2}}) \, dt\\ = 6t + \frac{t^2}{2}+\frac{t^{3/2+1}}{3/2 + 1} \\ = 6t + \frac{t^2}{2}+\frac{t^{5/2}}{5/2} \\= 6t + \frac{t^2}{2}+2/5t^{5/2} + C$

5 0

3 years ago

(2 x 10) + (9 x 1) + (7 x 1/10) + (8x 1/1000) in standard form

Pepsi [2]

Answer:The number is 209.708

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

The Laplace Transform of a function f(t), which is defined for all t > 0, is denoted by L{f(t)} and is defined by the imprope

lesya692 [45]

(1) D

$L_s\left\{t\right\} = \displaystyle\int_0^\infty te^{-st}\,\mathrm dt$

Integrate by parts, taking

$u = t \implies \mathrm du=\mathrm dt$

$\mathrm dv = e^{-st}\,\mathrm dt \implies v=-\dfrac1se^{-st}$

Then

$L_s\left\{t\right\} = \displaystyle \left[-\frac1ste^{-st}\right]\bigg|_{t=0}^{t\to\infty}+\frac1s\int_0^\infty e^{-st}\,\mathrm dt$

$L_s\left\{t\right\} = \displaystyle \frac1s\int_0^\infty e^{-st}\,\mathrm dt$

$L_s\left\{t\right\} = \displaystyle -\frac1{s^2}e^{-st}\bigg|_{t=0}^{t\to\infty}$

$L_s\left\{t\right\} = \displaystyle \boxed{\frac1{s^2}}$

(2) A

$L_s\left\{1\right\} = \displaystyle\int_0^\infty e^{-st}\,\mathrm dt$

$L_s\left\{1\right\} = \displaystyle\left[-\frac1se^{-st}\right]\bigg|_{t=0}^{t\to\infty}$

$L_s\left\{1\right\} = \displaystyle\boxed{\frac1s}$

7 0

3 years ago

Which of the following are solutions to the equation below?<br><br> (4x-1)^2=11

poizon [28]

You have to use the quadratic formula to solve this. when you do, you get x values of 1.079 and -.5791. You did not provide choices but that's what it comes out to.

4 0

3 years ago