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cupoosta [38]
4 years ago
4

How do I solve for y in this equation? 3xy-28=15x

Mathematics
1 answer:
Montano1993 [528]4 years ago
3 0

Answer:

  x = 28/(3y -15)

Step-by-step explanation:

Put the x-terms on the same side of the equal sign and everything else on the other side. Divide by the coefficient of x.

  3xy -28 = 15x . . . . . . given

  -28 = 15x -3xy . . . . . subtract 3xy

  -28 = x(15 -3y) . . . . . factor out x

  -28/(15 -3y) = x . . . . . . divide by the coefficient of x

We prefer to have a positive sign where possible, so we can multiply this by -1/-1 to get ...

  x = 28/(3y -15)

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