3 years ago

Points are identified in pictures by

Mathematics

1 answer:

ollegr [7]3 years ago

7 0

Answer:

Graphs

Step-by-step explanation:

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18-3b for b=4 please help

IrinaVladis [17]

Answer:

im sorry I don't know I didn't do stuff like this in school

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2 years ago

Write the sum of the numbers as the product of their gcf and another sum 32 and 20

pav-90 [236]

Ymm makes no sense but its pulsing so yea the answer is 52

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3 years ago

8 over 15? is it closer to 0, 1 over 2 or 1

ruslelena [56]

8/15 is about 0.53
It would be closer to 1/2 or 1 over 2

4 0

3 years ago

Read 2 more answers

A president, treasurer, and secretary, all di erent, are to be chosen from a club consisting of 12 people (whose names are I, J,

Ierofanga [76]

Answer:

There are 220 choices

Step-by-step explanation:

Given

$People = 12$

$Selection =3$ (President, Treasurer and Secretary)

Required

Determine number of selection (if no restriction)

This is calculated using the following combination formula:

$^nC_r = \frac{n!}{(n - r)!r!}$

Where

$n = 12$

$r= 3$

So, we have:

$^nC_r = \frac{n!}{(n - r)!r!}$

$^{12}C_3 = \frac{12!}{(12 - 3)!3!}$

$^{12}C_3 = \frac{12!}{9!3!}$

$^{12}C_3 = \frac{12*11*10*9!}{9!3!}$

$^{12}C_3 = \frac{12*11*10}{3!}$

$^{12}C_3 = \frac{12*11*10}{3*2*1}$

$^{12}C_3 = \frac{12*11*10}{6}$

$^{12}C_3 = 2*11*10$

$^{12}C_3 = 220\ ways$

There are 220 choices

8 0

3 years ago

The radius of a circle is 8 feet. What is the area of sector bounded by a 90° arc?

Lera25 [3.4K]

Since 90 degree is 1/4 of a circle, the area will be 1/4 th area of the full circle.

The radius is given by, r = 8 ft, therefore, the area of the full circle is,

$\begin{gathered} A=\pi\times r^2 \\ A=3.14\times8^2=200.96ft^2 \end{gathered}$

Therefore, the area of the sector is,

$A^{\prime}=\frac{1}{4}\times200.96ft^2=50.24ft^2$ $\begin{gathered} A^{\prime}=\frac{\theta}{360}\times\pi\times r^2 \\ \text{ =}\frac{\text{90}}{360}\times\pi\times8^2 \\ \text{ =}\frac{1}{4}\pi\times64=16\pi \end{gathered}$

4 0

2 years ago

Points are identified in pictures by​

Points are identified in pictures by