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3 years ago

What are the side lengths of a 45-45-90 triangle with a hypotenuse of 10root2?

Mathematics

1 answer:

scoundrel [369]3 years ago

6 0

Answer:

Step-by-step explanation:

let the lengths of sides=x (each)

x²+x²=(10√2)²

2x²=100×2

x²=100

x=√100=10

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Please help math i will give good rating and 5 stars if answer question

Talja [164]

Hey!

Let's walk through this together.

Possible Answers: {5, 7, 9, 11, 13}

Let's start with 5.

5-4<8

1<8

So, 5 is CORRECT.

Next, 7.

7-4<8

3<8

So, 7 is CORRECT.

Next, 9.

9-4<8

5<8

So, 9 is CORRECT.

Next, 11.

11-4<8

7<8

So, 11 is CORRECT.

Last, 13.

13-4<8

11<8

So, 13 is INCORRECT.

Your answers are: {5,7,9,11}

So D.

Hope this helps!

<h2><em>~~~PicklePoppers~~~</em></h2>

4 0

2 years ago

Kate wants to buy a new bicycle from a sporting goods store. The bicycle she wants normally sells for $800. The store has a sale

klio [65]

Answer:

700 dollars.

Step-by-step explanation:

The sale price is basically the new price of the bycicle. Therefore, is all bycicles cost 7/8 of their normal value, $\frac{7}{8} (800)=700$ . So during this sale at the sporting goods store, the bycicle would cost 700 dollars.

7 0

3 years ago

Read 2 more answers

Please tell me answers

Anna11 [10]

Answer:

no 8 is 90° and no 9 is two

Step-by-step explanation:

90° and two circles can pass through a given point

8 0

3 years ago

The graph of y=f(x) is shown below. Determine the value of x when f(x)=3?

emmasim [6.3K]

Answer:

f(x) = 3

y = 3

So from the graph the value of y = 3 is found D.

Thus x = -3.

All the best!

6 0

3 years ago

Read 2 more answers

please show on graph (with x and y coordinates) state where the function x^4-36x^2 is non-negative, increasing, concave up

babunello [35]

Answer:

$y'' =12x^2 -72=0$

And solving we got:

$x=\pm \sqrt{\frac{72}{12}} =\pm \sqrt{6}$

We can find the sings of the second derivate on the following intervals:

$(-\infty$ Concave up

$x=-\sqrt{6}, y =-180$ inflection point

$(-\sqrt{6}$ Concave down

$x=\sqrt{6}, y=-180$ inflection point

$(\sqrt{6}$ Concave up

Step-by-step explanation:

For this case we have the following function:

$y= x^4 -36x^2$

We can find the first derivate and we got:

$y' = 4x^3 -72x$

In order to find the concavity we can find the second derivate and we got:

$y'' = 12x^2 -72$

We can set up this derivate equal to 0 and we got:

$y'' =12x^2 -72=0$

And solving we got:

$x=\pm \sqrt{\frac{72}{12}} =\pm \sqrt{6}$

We can find the sings of the second derivate on the following intervals:

$(-\infty$ Concave up

$x=-\sqrt{6}, y =-180$ inflection point

$(-\sqrt{6}$ Concave down

$x=\sqrt{6}, y=-180$ inflection point

$(\sqrt{6}$ Concave up

8 0

3 years ago