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ki77a [65]
4 years ago
9

The fuel for nuclear fission in nuclear reactors is ____.

Chemistry
2 answers:
NikAS [45]4 years ago
7 0
<h2>Answer:</h2>

The correct answer is option D which is uranium.

<h3>Explanation:</h3>
  • Nuclear reactors are used for the production of nuclear energy.
  • Nuclear reactors contains uranium rods. Uranium undergoes nuclear fission when it absorbs one neutron producing two new nuclei and 3 neutron and large amount of energy.
  • Petroleum, carbon and hydrogen can not be used in nuclear reactors.
faust18 [17]4 years ago
6 0
The answer is D Uranium. 
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How many grams of KCl are needed to prepare 0.750 L of a 1.50 M solution in water?
dlinn [17]

Answer: Option A) 83.9g

Explanation:

KCl is the chemical formula of potassium chloride.

Given that,

Amount of moles of KCl (n) = ?

Volume of KCl solution (v) = 0.75L

Concentration of KCl solution (c) = 1.5M

Since concentration (c) is obtained by dividing the amount of solute dissolved by the volume of solvent, hence

c = n / v

make n the subject formula

n = c x v

n = 1.5M x 0.75L

n = 1.125 mole

Now given that,

Amount of moles of KCl (n) = 1.125

Mass of KCl in grams = ?

For molar mass of KCl, use the molar masses of:

Potassium, K = 39g;

Chlorine,Cl = 35.5g

KCl = (39g + 35.5g)

= 74.5g/mol

Since, amount of moles = mass in grams / molar mass

1.125 mole = m / 74.5g/mol

m = 1.125 mole x 74.5g/mol

m = 83.81g

Thus, 83.9 grams of KCl are needed to prepare 0.750 L of a 1.50 M solution in water

3 0
3 years ago
The instruction booklet for your pressure cooker indicates that its highest setting is 11.8 psipsi . You know that standard atmo
zavuch27 [327]

<u>Answer:</u> The temperature at which the food will cook is 219.14°C

<u>Explanation:</u>

To calculate the final temperature of the system, we use the equation given by Gay-Lussac Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{P_1}{T_1}=\frac{P_2}{T_2}

where,

P_1\text{ and }T_1 are the initial pressure and temperature of the gas.

P_2\text{ and }T_2 are the final pressure and temperature of the gas.

We are given:

P_1=14.7psi\\T_1=273K\\P_2=(14.7+11.8)psi=26.5psi\\T_2=?

Putting values in above equation, we get:

\frac{14.7psi}{273K}=\frac{26.5psi}{T_2}\\\\T_2=\frac{26.5\times 273}{14.7}=492.14K

Converting the temperature from kelvins to degree Celsius, by using the conversion factor:

T(K)=T(^oC)+273

492.14=T(^oC)+273\\\\T(^oC)=219.14^oC

Hence, the temperature at which the food will cook is 219.14°C

7 0
3 years ago
Part 1: Describe the mass and surface temperature of the supergiant stars.
Julli [10]
Part 1 :- Super gaint star have mass from 10 to 70 solar masses and brightness from 30,000 upto hundreds of thousand times the solar luminosity 
blue super giant surface temperature is 20,000 to 50,000 degree Celsius example :0 Rigel  its mass is around 20 times the sun mass it give light which 60,000 sun together give . 
part 2 :-   HR diagram : hertzsprung -Russel diagram ( attached below)

3 0
3 years ago
Balance the following chemical equation: <br> ___HCO + ___O —&gt; ___H2 + ___CO3
yawa3891 [41]

Answer: 2HCO + 4O → H2 + 2CO3

Explanation: Oxomethyl + Oxygen = Dihydrogen + Carbon Trioxide

Reaction Type: SINGLE REPLACEMENT

***If you found my answer helpful, please give me the brainliest, please give a nice rating, and the thanks ( heart icon :) ***

7 0
3 years ago
Sugar dissolving in warm water is chemical or phyiscal change
BlackZzzverrR [31]
Hey there! Great question;) Answer:Physical change Explanation: When sugar mixes with water, at the end, the chemical formulas are the same. Nothing has changed! I hope this helps;)
5 0
3 years ago
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