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Artyom0805 [142]
3 years ago
11

How much heat is required to raise the temperature of 25.0 grams of waterfrom 75.0°C to its boiling point?

Chemistry
1 answer:
Sav [38]3 years ago
5 0

Answer:

How much heat is required to raise the temperature of 25.0 grams of waterfrom 75.0°C to its boiling point?

Explanation:

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Not yet answered Marked out of 2.00 What is the concentration of NH4+ in 60.0 mL of a 0.50 M solution of (NH4)3PO4? (To write yo
Softa [21]

Answer : The concentration of NH_4^+ ion is 0.15E^1M

Explanation :

First we have to calculate the moles of (NH_4)_3PO_4.

\text{Moles of }(NH_4)_3PO_4=\text{Concentration of }(NH_4)_3PO_4\times \text{Volume of solution}=0.50M\times 0.06L=0.03mole

The balanced chemical reaction will be:

(NH_4)_3PO_4\rightleftharpoons 3NH_4^++PO_4^{3-}

From the reaction we conclude that,

1 mole of (NH_4)_3PO_4 dissociate to give 3 moles of NH_4^+ ion and 1 mole of PO_4^{3-} ion

So,

0.03 mole of (NH_4)_3PO_4 dissociate to give 3\times 0.03=0.09 moles of NH_4^+ ion and 0.03 mole of PO_4^{3-} ion

Now we have to calculate the concentration of NH_4^+ ion.

\text{Concentration of }NH_4^+=\frac{\text{Moles of }NH_4^+}{\text{Total volume}}

\text{Concentration of }NH_4^+=\frac{0.09mole}{0.06L}=1.5M=0.15E^1M

Therefore, the concentration of NH_4^+ ion is 0.15E^1M

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